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3 years ago

I need help with this question

Mathematics

2 answers:

satela [25.4K]3 years ago

7 0

Answer:

all you need to do is say if you agree or disagree and put when you think that! :)

horrorfan [7]3 years ago

5 0

I disagree because the line intersects at (0, 5) in the y-axis.

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Is -0.85 greater less than or equal to -0.98

Art [367]

Answer:

-0.85 > -0.98

-0.85 is greater than -0.98

Step-by-step explanation:

when comparing two number . . . you usually look first at the ones places, then if they are equal, then you look at the tens place, then then farther back untill one number is larger than the other.

However with negive numbers, you are looking to see the smaller number (closer to zero)

so -0.85 is (smaller in a sense) but is less negetive

-0.98 is farther from zero

hope this helped. please mark me brainliest!

5 0

3 years ago

I really need help and I have to show my work

Amanda [17]

10 lbs/$12= 1 lb/x dollars.
If you rewrite it up and down and not slanted, it would be clearer to understand, but anyways, you cross multiply:
12*1=12
12/10= 1.2
So the answer is 1.2, if you put it on that bubble sheet, put 1, then a decimal, after the decimal 2, and then all 0's,.

8 0

3 years ago

If a factory can produce 800 newspaper in 15 minutes how many newspapers will it produce in 2 hours

Irina18 [472]

Answer:

it will produce 6400 newspapers

Step-by-step explanation:

800 x 8 = 6400

4 0

3 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

B is two-fifth of c

notka56 [123]

Answer:

8a:15b:6c

a:b:c = 8:15:6

7 0

3 years ago

I need help with this question ​

I need help with this question