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3 years ago

Please help!

Mathematics

2 answers:

Lynna [10]3 years ago

8 0

Answer:

4 liters of 5% solution and 16 liters of 17.5% solution we need.

Step-by-step explanation:

Let us assume that x liters of 5% solution and y liters of 17.5% solution are taken.

So, x + y = 20 ........ (1)

As the final solution is of 15%, so we can write

⇒ 5x + 17.5y = 300 ......... (2)

Now, solving equations (1) and (2) we get,

17.5y - 5y = 200

⇒ 12.5y = 200

⇒ y = 16 liters

Hence, x = 20 - y = 4 liters.

Therefore, 4 liters of 5% solution and 16 liters of 17.5% solution we need. (Answer)

aleksklad [387]3 years ago

4 0

Answer:

4 liters of 5% solution and 16 liters of 17.5% solution we need.

Step-by-step explanation:

Let us assume that x liters of 5% solution and y liters of 17.5% solution are taken.

So, x + y = 20 ........ (1)

As the final solution is of 15%, so we can write

$\frac{\frac{5x}{100}+ \frac{17.5y}{100}}{x + y} = \frac{15}{100}$

⇒ 5x + 17.5y = 300 ......... (2)

Now, solving equations (1) and (2) we get,

17.5y - 5y = 200

⇒ 12.5y = 200

⇒ y = 16 liters

Hence, x = 20 - y = 4 liters.

Therefore, 4 liters of 5% solution and 16 liters of 17.5% solution we need. (Answer)

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A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat

sladkih [1.3K]

<h2>Question: </h2>

A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat at a gain of 10% and the spoiled when at a loss of 25%. Find his total gain or loss per cent.

Answer:

<h2>step by step answer:</h2>

In the question we are given a shopkeeper or bought wheat for Rs. 35000. Now, due to leakage 17 of the total wheat is spoiled. Now, he sold the good wheat at 10% gain and the bad wheat at 25% loss. We need to find the total gain/loss percent.

According to the problem, the total cost of wheat is Rs. 35000.

Now, let us find the cost price of the spoiled wheat.

So, the cost of spoiled wheat is 17×Rs35000 which is equal to Rs. 5000.

Hence, the cost price of spoiled wheat is Rs 5000.

As we know that the spoiled wheat was sold at 25% loss, so we can say that if the cost price is considered as 100% so the selling price is considered as (100−25)% or 75%.

So, we got the selling price of spoiled wheat is 75100×5000=Rs3750

So, the cost price of spoiled wheat is Rs.5000 and selling price of spoiled wheat is Rs.3750.

Now, let us find the cost price of the good wheat.

Now, we will consider the good quality of wheat whose cost price is Rs(35000−5000) which is Rs. 30000.

Hence, the cost price is Rs. 30000.

As we know good quality wheat was sold at 10% gain so we can say that, if the cost price is 100% then the selling price will be (100+10)% or 110% .

Hence, the selling price of good quality wheat is 110100×Rs30000 which is Rs. 33000.

So, the cost price of good quality wheat is Rs. 30000 and selling price is Rs. 33000.

Let us find the total selling price of the wheat that the shopkeeper bought.

Now the total selling price of the wheat is Rs.3750+Rs.30000=Rs.36750.

Hence Profit = Total selling price − Total cost price

profit =Rs.36750−Rs.35000

=Rs.1750

profit %

=profitcost price×100%.

=175035000×100%.

=5%.

<h2>So, total profit is 5%.</h2>

6 0

3 years ago

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10 points<br> Ray BD bisects

Eduardwww [97]

I think Its BC or ABC

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4 years ago

The slope of a line passing through H (-2, 5) is -3/4. Which ordered pair represents a point on this line?

oksano4ka [1.4K]

Answer:
(6,-1)

Explanation:
The slope of the line can be calculated using the following formula:
slope = $\frac{y2-y1}{x2-x1}$

We are given that:
slope = -0.75
point (x1,y1) is (-2,5)

We will use each of the given points to calculate the corresponding slope, then compare the calculated slope with the given one.

For point (6,-1):
slope = $\frac{-1-5}{6--2}$ = -0.75 ........> accepted choice

For point (2,8):
slope = $\frac{8-5}{2--2}$ = 0.75 ........> rejected choice

For point (-5,1):
slope = $\frac{1-5}{-5--2}$ = 4/3 ........> rejected choice

For point (1,1):
slope = $\frac{1-5}{1--2}$ = -4/3 ........> rejected choice

Therefore, the first option is the only correct one.

Hope this helps :)

5 0

3 years ago

I need help asap :):);)

den301095 [7]

Answer: The third option.

Step-by-step explanation:

This is an equation because it has an equals sign that can be solved for, making it an equation.

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Prove the following identity

Deffense [45]

Answer:

sec(x)/(tan xsin(x))=cot^2 x+1 = Ture

Step-by-step explanation:

Verify the following identity:

sec(x)/(tan(x) sin(x)) = cot(x)^2 + 1

Hint: | Eliminate the denominator on the left hand side.

Multiply both sides by sin(x) tan(x):

sec(x) = ^?sin(x) tan(x) (cot(x)^2 + 1)

Hint: | Express both sides in terms of sine and cosine.

Write cotangent as cosine/sine, secant as 1/cosine and tangent as sine/cosine:

1/cos(x) = ^?sin(x)/cos(x) sin(x) ((cos(x)/sin(x))^2 + 1)

Hint: | Simplify the right hand side.

((cos(x)/sin(x))^2 + 1) sin(x) (sin(x)/cos(x)) = (((cos(x)^2)/(sin(x)^2) + 1) sin(x)^2)/(cos(x)):

1/cos(x) = ^?(sin(x)^2 (cos(x)^2/sin(x)^2 + 1))/cos(x)

Hint: | Put the fractions in cos(x)^2/sin(x)^2 + 1 over a common denominator.

Put cos(x)^2/sin(x)^2 + 1 over the common denominator sin(x)^2: cos(x)^2/sin(x)^2 + 1 = (cos(x)^2 + sin(x)^2)/sin(x)^2:

1/cos(x) = ^?sin(x)^2/cos(x) (cos(x)^2 + sin(x)^2)/sin(x)^2

Hint: | Cancel down ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)).

Cancel sin(x)^2 from the numerator and denominator. ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)) = (sin(x)^2 (cos(x)^2 + sin(x)^2))/(sin(x)^2 cos(x)) = (cos(x)^2 + sin(x)^2)/cos(x):

1/cos(x) = ^?(cos(x)^2 + sin(x)^2)/cos(x)

Hint: | Eliminate the denominators on both sides.

Multiply both sides by cos(x):

1 = ^?cos(x)^2 + sin(x)^2

Hint: | Use the Pythagorean identity on cos(x)^2 + sin(x)^2.

Substitute cos(x)^2 + sin(x)^2 = 1:

1 = ^?1

Hint: | Come to a conclusion.

The left hand side and right hand side are identical:

Answer: (identity has been verified)

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2 years ago