Angular width is 3 x 10^-3
Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,
where λ is wavelength
Given:
λ = 450 nm = 450×10^−9m
d = 0.3x10^−3m, D = 1m
W = 2 x 450×10^−9/0.3x10^−3*1
To Find:
Angular width
Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima
θ = W/D
θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3
Hence, angular width is 3 x 10^-3
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Sounds are created when something vibrates (shakes back and forth), sending waves of vibrations into the ears of the listener. When a bell is struck, the metal vibrates. The vibrations travel through the air as sound waves.
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<u>Given;</u>
mass m = 75 kg
acceleration a = 24.5 ms²
<em>F = ma </em>
F = 75 kg * 24.5 ms²
= 1837.5 kg ms².
