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andreev551 [17]
3 years ago
8

Question 6(Multiple Choice Worth 2 points)

Physics
1 answer:
nikklg [1K]3 years ago
8 0

I believe the answer is the first one.

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A driver who does not wear a seat belt continues to move at the initial velocity until she or he hits something solid (e.g the s
egoroff_w [7]

This question is incomplete, the complete question is;

Seatbelts provide two main advantages in a car accident (1) they keep you from being thrown from the car and (2) they reduce the force that acts on your during the collision to survivable levels. This second benefit can be illustrated by comparing the net force encountered by a driver in a head-on collision with and without a seat beat.  

1) A driver wearing a seat beat decelerates at roughly the same rate as the car it self. Since many modern cars have a "crumble zone" built into the front of the car, let us assume that the car decelerates of a distance of 1.1 m. What is the net force acting on a 70 kg driver who is driving at 18 m/sec and comes to rest in this distance?

Fwith belt =

2) A driver who does not wear a seat belt continues to move at the initial velocity until she or he hits something solid (e.g the steering wheel) and then comes to rest in a very short distance. Find the net force on a driver without seat belts who comes to rest in 1.1 cm.

Fwithout belt =

Answer:

1) The Net force on the driver with seat belt is 10.3 KN

2) the Net force on the driver without seat belts who comes to rest in 1.1 cm is 1030.9 KN

Explanation:

Given the data in the question;

from the equation of motion, v² = u² + 2as

we solve for a

a = (v² - u²)/2s ----- let this be equation 1

we know that, F = ma ------- let this be equation 2

so from equation 1 and 2

F = m( (v² - u²)/2s )

where m is mass, a is acceleration, u is initial velocity, v is final velocity and s is the displacement.

1)

Wearing sit belt, car decelerates of a distance of 1.1 m. What is the net force acting on a 70 kg driver who is driving at 18 m/sec and comes to rest in this distance.

i.e, m = 70 kg, u = 18 m/s, v = 0 { since it came to rest }, s = 1.1 m

so we substitute the given values into the equation;

F = 70( ((0)² - (18)²) / 2 × 1.1 )

F = 70 × ( -324 / 2.4 )

F = 70 × -147.2727

F = -10309.09 N

F = -10.3 KN

The negative sign indicates that the direction of the force is opposite compared to the direction of the motion.

Fwith belt =  10.3 KN

Therefore, Net force of the driver is 10.3 KN

2)

No sit belt,  

m = 70 kg, u = 18 m/s, v = 0 { since it came to rest }, s = 1.1 cm = 1.1 × 10⁻² m

we substitute

F = 70( ((0)² - (18)²) / 2 × 1.1 × 10⁻² )

F = 70 × ( -324 / 0.022 )

F = 70 × -14727.2727

F = -1030909.08 N

F = -1030.9 KN

The negative sign indicates that the direction of the force is opposite compared to the direction of the motion.

Fwithout belt = 1030.9 KN

Therefore, the net force on the driver without seat belts who comes to rest in 1.1 cm is 1030.9 KN

4 0
3 years ago
What would happen to life on earth if all the plants died? plz help
denis-greek [22]

Answer:

we would have no oxygen and barely any water.

4 0
3 years ago
Read 2 more answers
Who's in highschool? lol, It said ask a question
natita [175]
About 76.3% who use this site if what they selected it true
3 0
3 years ago
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How much work does a bricklayer do to carry 30.2 kg of bricks from the ground up to the third floor (height = 11.1 m) of a build
Julli [10]

Answer:

Work done by the bricklayer, W = 3.285 kJ

Therefore, the gravitational potential energy of the brick-Earth system =  3.285 kJ

Explanation:

Work done is the product of applied force and distance moved by the force.

The force on an object in the gravitational field is equal to the product of the mass of the object and acceleration due to gravity This force is the weight of the object or body. In lifting an object from a lower height to a higher one, the distance moved is equal to the increase in height.

Work done in lifting an object in a gravitational field = mgh

where m = mass of the object, g = acceleration due to gravity, h = height

From the question, m = 30.2 kg, g = 9.8 m/s², h = 11.1 m

Work done by the bricklayer = 30.2 * 9.8 * 11.1 = 3285.156 J

Work done by the bricklayer, W = 3.285 kJ

Gravitational Potential Energy, PEg = mgh = W

Therefore, the gravitational potential energy of the brick-Earth system =  3.285 kJ

7 0
2 years ago
Let's say Laura wants to learn more about six-foot (1.8-meter) tubeworms. She would find the most information by __________.
Harrizon [31]

i think the answer is C because tube worms live in the ocean.

Explanation:

tube worms live in the ocean

7 0
1 year ago
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