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hammer [34]
3 years ago
8

Two horses are pulling a box in two different directions as shown in the below image. The image shows one 30.0 N force due north

and one 30.0 N force due east.
What is the magnitude of the force needed to stop the horses and bring the box into equilibrium? Describe your calculations. Where would you locate the rope to apply the force?

Physics
1 answer:
Novay_Z [31]3 years ago
4 0

Explanation:

'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.

'Where would you locate the rope to apply the force?' - in point D.

PS. zoom out the attached picture.

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Low air pressure systems are usually associated with which type of weather?
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Consider a particle with unit charge q, and mass m, in a constant magnetic field B directed along the positive z–axis. The parti
max2010maxim [7]

Answer:

it must be helical motion in which the charge particle will move uniformly along z axis and simultaneously it will move in circular path in xy plane.

Explanation:

Magnetic field is along z axis while velocity is in x-z plane

so we will have

F = q(\vec v \times \vec B)

so here we can say

F = q(u\hat i + w\hat k) \times (B \hat k)

so we will have

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so here the net force on the charge is perpendicular to its x directional velocity along - Y direction

So due to this component of motion it will move along a circle while other component of the motion will remain uniform always

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1) Uniform circular motion

2) Uniform motion

So we can say that it must be helical motion in which the charge particle will move uniformly along z axis and simultaneously it will move in circular path in xy plane.

4 0
3 years ago
Mildred takes a pound of frozen hamburger meat out of the freezer and puts it into the refrigerator.
Hatshy [7]
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3 years ago
Pedro e Maria saíram para passear de carro. Eles partiram de São Paulo às 10 h em direção à Braúna, localizada a 500 km da capit
Salsk061 [2.6K]

Answer:

This can be translated to:

"P edro and Maria went for a drive. They left São Paulo at 10 am towards Braúna, located 500 km from the capital. As the journey was long, they made two 15-minute stops for gas and also spent 45 minutes for lunch. When arriving at the final destination, Maria looked at the clock and saw that it was 6 pm. What is the average speed of the trip?"

Ok, the first thing we know is, that for the average speed we can write:

Speed = Distance/time.

First, we know that Distance = 500km.

And for the time we have two possiblities:

The total average speed will decrease because they were stopped a total of:

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Then if the travel starts at 10am, and ends at 6 pm, the total time that has passed is:

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6pm - 10am = 18 - 10 = 8hs

Then the average speed will be:

Speed = 500km/8h = 62.5 km/h.

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Then the average speed would be:

Speed = 500km/6.75h = 74.1 km/h

4 0
3 years ago
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