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hammer [34]
3 years ago
8

Two horses are pulling a box in two different directions as shown in the below image. The image shows one 30.0 N force due north

and one 30.0 N force due east.
What is the magnitude of the force needed to stop the horses and bring the box into equilibrium? Describe your calculations. Where would you locate the rope to apply the force?

Physics
1 answer:
Novay_Z [31]3 years ago
4 0

Explanation:

'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.

'Where would you locate the rope to apply the force?' - in point D.

PS. zoom out the attached picture.

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I need help ASAP plzzzz
Fiesta28 [93]

Answer:

a) 1.75s b) 17.2 m/s (down)

Explanation:

d1= 15m d2= 0m (because it hits ground)

a= -9.81 m/s^2 t=???

Equation

the triangle means change in so d2-d1

Δd= v1 * t + 1/2 * a * t^2

0m-15m= v1*t + 1/2 a t^2

-15 m= 0m/s*t (goes away) + 1/2* a *t^2

-15mx2= t^2

-15mx2/a= t^2

Square root (-30/-9.81m/s^2)

t=1.75 s

b) now v2!!

Im going to use v2= v1 + a*t

v2= 0m/s + -9.81 x 1.75s

v2 = -17.2 m/s or you can say 17.2 m/s down!!!

7 0
3 years ago
How are electric and magnetic forces the same? How are they different?
qaws [65]
They both have a certain force. They are different because that force is different
3 0
3 years ago
A vector must always have both size and ..
DochEvi [55]
Both magnitude and DIRECTION
For example,
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5 0
3 years ago
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Daniel [21]

Answer:

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6 0
3 years ago
A normal walking speed is around 2.0 m/s . how much time t does it take the box to reach this speed if it has the acceleration 5
creativ13 [48]

Given:

u(initial velocity)=0

a=5.54m/s^2

v(final velocity)=2 m/s

v=u +at

Where v is the final velocity.

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a is the acceleration.

t is the time

2=0+5.54t

t=2/5.54

t=0.36 sec


6 0
3 years ago
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