Two horses are pulling a box in two different directions as shown in the below image. The image shows one 30.0 N force due north
and one 30.0 N force due east.
What is the magnitude of the force needed to stop the horses and bring the box into equilibrium? Describe your calculations. Where would you locate the rope to apply the force?
What is the magnitude of the force needed to stop the horses and bring the box into equilibrium? Describe your calculations. Where would you locate the rope to apply the force?
1 answer:
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Answer:
Pressure on both feet will be
Explanation:
Weight of the person F = 500 N
Area of foot print
Area of both the foot
We have to find pressure on both the feet
Pressure is equal to ratio of force and area
So pressure
So the pressure on both feet will be when person stands on both feet.
1) Impulse: -32,000 kg m/s
The impulse acting on the car is equal to the change in momentum of the car:
where in this problem we have
m = 1000 kg is the mass of the car
v = 0 m/s is the final velocity of the car
u = 32 m/s is the initial velocity of the car
Substituting values into the equation, we find
2) -4751 N
The impulse exerted on the car is also equal to the product between the average force, F, and the duration of the collision, t:
where in this situation we know
is the impulse
t = 7 s is the duration of the collision
Solving the formula for F, we find the average force:
and the negative sign means that the force is in the opposite direction to the motion of the car.