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hammer [34]
3 years ago
8

Two horses are pulling a box in two different directions as shown in the below image. The image shows one 30.0 N force due north

and one 30.0 N force due east.
What is the magnitude of the force needed to stop the horses and bring the box into equilibrium? Describe your calculations. Where would you locate the rope to apply the force?

Physics
1 answer:
Novay_Z [31]3 years ago
4 0

Explanation:

'What is the magnitude of the force needed to stop the horses and bring the box into equilibrium?' ≈42N; according to the vectors rules.

'Where would you locate the rope to apply the force?' - in point D.

PS. zoom out the attached picture.

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If i was feeling harsh today, I'd say the answer to your question is impossible to obtain due to the fact that photons do not emit radiation, photons ARE the radiation emitted. Though for the sake of it, here is the method...

<u>The simple method:
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E=hf

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In January 2004, NASA landed exploration vehicles on Mars. Part of the descent consisted of the following stages:
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Acceleration is given by:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval

Let's apply the formula to the different parts of the problem:

A) -20.5 m/s^2

Let's convert the quantities into SI units first:

u = 19300 km/h \cdot \frac{1000 m/km}{3600 s/h} = 5361.1 m/s

v=1600 km/h  \cdot \frac{1000 m/km}{3600 s/h}  =444.4 m/s

t = 4.0 min = 240 s

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u = 444.4 m/s

v=321 km/h  \cdot \frac{1000 m/km}{3600 s/h}  =89.2 m/s

t = 94 s

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a=\frac{89.2 m/s - 444.4 m/s}{94 s}=-3.8 m/s^2

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a is the acceleration

d = 75 m is the distance covered

Solving for a, we find

a=\frac{v^2-u^2}{2d}=\frac{0^2-(89.2 m/s)^2}{2(75 m)}=-53.0 m/s^2

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