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andrew11 [14]
2 years ago
12

Which equation is equivalent to the formula m = ca? a = cm a equals m over c c = am c equals a over m.

Mathematics
2 answers:
disa [49]2 years ago
8 0

The option b which is a=\dfrac{m}{c} is correct answer.

Given to us:

m=ca

dividing both sides by c, we get

m=ca\\\\\dfrac{m}{c}=\dfrac{ca}{c}

canceling c from right hand side, we get

\dfrac{m}{c}=a \\\\a=\dfrac{m}{c}

Therefore, the option b which is a=\dfrac{m}{c} is correct answer.

To know more visit:

brainly.com/question/9559346

Svet_ta [14]2 years ago
6 0

Answer:

a = m/c

Step-by-step explanation:

I translated the paragraph into these options.  Please check accuracy.

m = ca?

a = cm   No,  a = m/c

a = m/c <u>Yes</u>

c = am   No,  c = m/a

c = a/m  No,  c = m/a

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(D) <em>f(x)</em> = <em>x</em> ² +<em> </em>4<em>x</em> - 1   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 4 (<em>x</em> + <em>h</em>) - 1 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 4<em>x</em> + 4<em>h</em> - 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ² + 4<em>h</em>

\implies \displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2+4h}h = \lim_{h\to0}(2x+h+4) = 2x+4

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