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ELEN [110]
3 years ago
11

What does it mean by type of angles and relationship between the angles if the line are parallel ?

Mathematics
1 answer:
valkas [14]3 years ago
6 0

Where two lines cross, four (4) angles are formed. Two adjacent angles that share a vertex can be called a "linear pair." Two non-adjacent angles that have the same vertex and the same lines for sides, are called "vertical angles."

Where a transversal crosses two parallel lines, eight (8) angles are formed, four (4) at each intersection. In addition to the above angle types, there are other relationships that can be described.

Angles can be called <em>corresponding</em>, if they are in the same location relative to the intersection point (both on the north-east corner, for example). Angles are <em>interior</em> if they are between the parallel lines; <em>exterior</em> of they are not. They get the additional descriptor of <em>opposite</em>, if they are on opposite sides of the transversal.

If the angles are not opposite, and share a side but not a vertex, they can be called <em>adjacent</em>. (Only <em>interior</em> angles can be adjacent, one pair on either side of the transversal.)

_____

With the above definitions in mind, several <u>relationships</u> arise where a transversal crosses parallel lines. (<u>Types</u> of angles are <em>italicized</em>.) Two examples of each type are listed by angle numbers. Angles 1 and 2 are a linear pair, for example.

Angles of a <em>linear pair</em> are supplementary. (1, 2), (5, 7)

<em>Vertical</em> angles are congruent. (1, 4), (6, 7)

<em>Adjacent</em> angles are supplementary. (3, 5), (4, 6)

<em>Corresponding</em> angles are congruent. (1, 5), (4, 8)

<em>Opposite interior</em> angles are congruent. (3, 6), (4, 5)

<em>Opposite exterior</em> angles are congruent. (1, 8), (2, 7)

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Leto [7]

The value of f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Given a function f(x)=4-2x+6x^{2}.

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6a^{2} (By just putting x=a).

f(a+h)==4-2(a+h)+6(a+h)^{2}

=4-2a-2h+6(a^{2} +h^{2} +2ah)

=4-2a-2h+6a^{2} +6h^{2} +12ah

=6a^{2} +6h^{2}-2a-2h+12ah

[f(a+h)-f(a)]/h=[6a^{2} +6h^{2}-2a-2h+12ah-(4-2a+6a^{2} )]/h

=(6a^{2} +6h^{2} -2a-2h+12ah)/h

=(6h^{2} -2h+12ah)/h

=6h+12a-2.

Hence the value of function f(a)=4-2a+6a^{2}, f(a+h) is 6a^{2} +6h^{2} -2a-2h+12ah , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6x^{2}.

Learn more about function at brainly.com/question/10439235

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Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

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The first one.

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