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suter [353]
3 years ago
10

Help me please, Domain & Range problem

Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

Domain: all reals

Range: 4 ≤y <∞

Step-by-step explanation:

The domain is the possible input values(x)

From the arrows at the left and right ends on the graph, the inputs can be all reals

The range is the possible output values (y)

Y goes from 4 to infinity

4 ≤y <∞

You might be interested in
(2^3 × 2)^2 pls explain how you got it....the answer is 2^8 but I want to know how we get that.
mario62 [17]

Step-by-step explanation:

(2³ × 2¹)²

(2⁶ × 2²)

for indices , × become +, plus

÷ become -, minus

so

2⁶+²

2⁸

6 0
3 years ago
Please help me! i need some to explain the equation for this.
topjm [15]

Answer:

  (b)  21.4

Step-by-step explanation:

There are a couple of interesting relations regarding chords and secants and tangents of a circle. With the right point of view, they can be viewed as variations of the same relation, possibly making them easier to remember.

When chords cross inside a circle (as here), each divides the other into two parts. The product of the lengths of the two parts of one chord is the same as the product of the lengths of the two parts of the other chord.

Here, that means ...

  7x = 10·15

  x = 150/7 = 21 3/7 ≈ 21.4

_____

<em>Additional comment</em>

A secant is a line that intersects a circle in two places. (A tangent is a special case of secant where the two points of intersection are the same point.) When two secants meet outside the circle, there is a special relation between the lengths of the various line segments.

Consider the line segment from the point where the secants meet each other to the far intersection point with the circle. The product of that length and the length to the near intersection point with the circle is the same for both secants.

Here's the viewpoint that merges these two relations:

<em>The product of the lengths from the point of intersection of the lines with each other to the two points of intersection with the circle is the same for each line</em>.

(Note that when the "secant" is a tangent, that product is the square of the distance from the tangent point to the point of intersection with the other line--the distance to the circle multiplied by itself.)

6 0
2 years ago
Read 2 more answers
Hey can you please help me posted picture of question
larisa [96]
(5x - 2)^2 = 15

Square root both sides:
5x - 2 = \pm\sqrt{15}

Add 2 to both sides:
5x = pm\sqrt{15} + 2

Divide both sides by 5:
x =  \dfrac{ \pm\sqrt{15} + 2}{5}

Answers:
x = \dfrac{ \sqrt{15} + 2}{5} \ or \ \dfrac{ - \sqrt{15} + 2}{5}

Answer: (B) and (E)

5 0
3 years ago
Read 2 more answers
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
What is the solution for -3(6x+5)-2(1-17x)=3(5+5x)
Novosadov [1.4K]

-3(6x+5)-2(1-17x)=3(5+5x)

Mutiply the first bracket by -3

(-3)(6x)= -18x

(-3)(5)= -15

Mutiply the second bracket by -2

(-2)(1)= -2

(-2)(-17x)= 34x

Mutiply the third bracket by 3

(3)(5)= 15

(3)(5x)= 15x

-18x-15-2+34x= 15+15x

-18x+34x-15-2= 15+15x

16x-17= 15+15x

move 15 to the other side

sign changes from +15 to -15

16x-17-15= 15-15+15x

16x-32= 15x

move -32 to the other side

sign changes from -32 to +32

16x-32+32=15x+32

16x= 15x+32

move 15x to the other side

sign changes from +15x to -15x

16x-15x=15x-15x+32

x= 32

Answer: x= 32

3 0
3 years ago
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