Ans.
Platelets are a type of blood cells, responsible for blood clotting. These cells prevent excessive blood loss from wound as they form plug or clot at the site of injury to repair the damage. Thus, the option). platelets is correctly matched with 'clotting blood.'
White blood cells or WBCs are components of immune system that protect the body from harmful foreign molecules, such as bacteria, fungi, and viruses and harmful body cells, such as tumor cells. Thus, the option). white blood cells is correctly matched with 'fighting bacteria.'
Red blood cells or RBCs are blood cells that transport oxygen, carbon dioxide, and nutrients to the different part of the body. These cells are made up of hemoglobin and protein. Thus, the option). red blood cells is correctly matched with 'clotting blood.'
Plasma is the non-cellular, colorless, fluid portion of blood, composed of proteins, vitamins, antibodies, amino acids, and other micromolecules. It is responsible for viscous nature of blood. Thus, the option). plasma is correctly matched with 'providing viscosity to the blood.'
That should be the cell membrane. The cell membrane acts as a filter in and out.
<span>The amino acid sequence contains the necessary information </span>to<span> determine how that particular </span>protein will<span> fold into a 3-dimensional structure as well as the stability of the resulting structure.</span>
Answer:
Explanation:
We can easily move the box from a ground floor though to the first floor at an angle of 40° to the horizontal by simply pushing the load through an inclined plane. We will simply be lean the inclined plane on the building at the required angle and the push through the the height of the building.
Based on the explanation above, the best type of simple machine to use is an INCLINED PLANE. <em>Note that the essence of using a machine is simply to make our work easier and faster and also be able to overcome a much larger load with a minimal effort. </em>
Answer:
Frequency of allele A1- 0.41
Explanation:
In Hardy weinberg equilibrium,
P refers to the dominant allele
q refers to the recessive allele
The allele frequency will be p+q=1
The genotypic frequency is- P²+q²+2pq=1
P²= genotype of dominant trait ( A1A1)- 77
2pq= genotype of heterozygotes (2pq)- 65
q²= genotype of recessive trait (A2A2)- 123
Total number of offsprings= 77+ 65+ 123
= 265
Now to calculate allele frequency of A1=
= 77/265 + 1/2( 65//265)
= 0.290+ 0.122
= 0.413
Thus, 0.41 is correct.
