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Assoli18 [71]
3 years ago
3

FACTORIZE. 9x2y-24xy2-16y3 solve it

Mathematics
2 answers:
Arisa [49]3 years ago
7 0
9x^2y-24xy^2-16y^3=y(9x^2-24xy-16y^2)\\\\=y(9x^2-24xy+16y^2-32y^2)=y[(3x)^2-2\cdot3x\cdot4y+(4y)^2-32y^2]\\\\=y[(3x-4y)^2-32y^2]=y[(3x-4y)^2-16\cdot2y)]\\\\=y[(3x-4y)^2-(4\sqrt2\ y)^2]=y(3x-4y-4\sqrt2\ y)(3x-4y+4\sqrt2\ y)
zhenek [66]3 years ago
6 0
9x2y - 24xy2 + 16y3

= y( 9x2 - 24xy + 16y2)

= y{ (3x)2 - 2(3x)(4y) + (4y)2 }

= y{ (3x - 4y)2 }

= y (3x -  4y) (3x -  4y)

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In the triangle below which of the following best describes dh​
siniylev [52]
Looks like an angle bisector to me
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Their is a rectangle that has measurements in inches. If the width is 7/8 of an inch and the height is 2/3 of an inch, what is t
Alex Ar [27]

Answer:

Area of a rectangle = 7/12 of an inch

Step-by-step explanation

Area of a rectangle = Length × width

In this case, the length is represented by height

Height = 2/3 of an inch

Width = 7/8 of an inch

Area of a rectangle = Length × width

= 2/3 × 7/8

= (2 * 7) / (3 * 8)

= 14 / 24

= 7 / 12

Area of a rectangle = 7/12 of an inch

7 0
3 years ago
31.68 is 45% of what number?
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31.68 is 45% of 70.4

n * 0.45 = 31.68
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8 0
3 years ago
Read 2 more answers
a rectangle has a lenghth of 2x+7 and a width of 3x+8y. Write and simplify an expression for the perimeter of that rectangle.
padilas [110]
The answer to this is 10x + 16y +14.
3 0
3 years ago
Read 2 more answers
A quiz has twenty questions with 7 points awarded for each correct answer, 2 points deducted for each wrong answer and 0 for eac
alexandr1967 [171]
<h3>Answer: Jack skipped 5 questions</h3>

(he got 2 wrong answers, and 13 correct answers)

=====================================================

Explanation:

c = number of correct answers

w = number of wrong answers

m = number of missing answers (ie, omitted answers)

7c = number of points awarded from just the correct answers

-2w = number of points awarded from the wrong answers. Note the negative to indicate we lose points here.

0m = 0 = points from the missing answers. We don't have to worry about this portion

In total, Jack would earn 7c-2w points. Since he actually earned 87 points, we can write the equation 7c-2w = 87. We'll come back to this later.

-----------------------

The quiz has 20 questions, so c+w+m = 20 is another equation we'll be working with. Solve for c to get c = -w-m+20. Plug this into the equation 7c-2w = 87 to get...

7c-2w = 87

7(-w-m+20)-2w = 87 ... replace c with (-w-m+20)

-7w-7m+140-2w = 87 ... distribute

-9w-7m+140 = 87

-9w-7m = 87-140

-9w-7m = -53

9w+7m = 53

----------------------

From here, you use trial and error. We don't have enough information to finish solving the system. We would need 3 equations to solve for the 3 unknowns.

What we can do is make a guess of what w could be and use that to find m. Luckily there is a small list of possible values for w.

So let's say w = 0

9w+7m = 53

9(0)+7m = 53 ... plug in w = 0

7m = 53

m = 53/7 ... divide both sides by 7

m = 7.57

We got a non-whole number, so there is no way w = 0 since we can't have 0.57 of a question missing. Jack either answers the question, or he skips it. He can't have both happen.

---------------------

Let's repeat for w = 1

9w+7m = 53

9(1)+7m = 53 ... replace w with 1

9+7m = 53

7m = 53-9 ... subtract 9 from both sides

7m = 44

m = 44/7 ... divide both sides by 7

m = 6.28

So we can see that w = 1 isn't possible either.

---------------------

However, w = 2 is possible

9w+7m = 53

9(2)+7m = 53

18+7m = 53

7m = 53-18

7m = 35

m = 35/7

m = 5

Meaning that Jack got w = 2 wrong answers and skipped over m = 5 questions. The number of correct answers is c = 20-m-w = 20-5-2 = 13

-----------------------------------

An alternative to using trial-and-error is to use a graph.

Replace w and m with x and y respectively. So we go from 9w+7m = 53 to 9x+7y = 53

Use a graphing tool, or plot the graph on graph paper, to get what you see in the diagram below. I used the program GeoGebra to graph.

Then notice how the graph goes through the point (2,5) which means x = 2 and y = 5. Replace x and y with w and m to find (w,m) = (2,5)

note: the point (5,1) looks like it also lies on the graph, but it is not a solution. It's just a point that is very close to the line. I recommend you try out (w,m) = (5,1) and you'll see it doesn't work.

3 0
3 years ago
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