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3 years ago

The hypotenuse of a right triangle is 7 inches, and one of the legs is inches. Find the length of the other leg. .

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

Pythagorian theorem:

7^2=13+b^2 -> b^2=49-13=36

The square root of 36 is obviously 6.

So, the other leg has a length of 6 inches

Step-by-step explanation:

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Determine if the events A and B are independent. Show all steps.

zmey [24]

Answer:

$P(A U B ) = \frac{13}{25}$

Step-by-step explanation:

STEP:-1

Given that events A and B are independent then

P(A ∩B ) = P(A) P(B)

Given that P(A) = 2/5 and P(B) = 1/5

STEP:- 2

P(A ∩B ) = P(A) P(B)

$P(A U B) = P(A) +P(B) - P(A n B )$

$P(A U B ) = P(A) +P(B) - P(A) P(B)$

Step(iii):-

$P(A U B ) = \frac{2}{5} +\frac{1}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{25}$

$P(A U B ) = \frac{15-2}{25} = \frac{13}{25}$

4 0

2 years ago

If (20, 14) is an ordered pair of the inverse of F(x), which of the following is an

Law Incorporation [45]

Answer:

A. (14,20)

Step-by-step explanation:

The inverse relation is found by swapping x and y in the ordered pair.

When ...

14 = f^-1(20)

then ...

20 = f(14)

The corresponding ordered pair is (14, 20).

3 0

3 years ago

Find dy/dx for (y^2/x) = 18 by implicit differentiation

Natasha2012 [34]

9514 1404 393

Answer:

dy/dx = y/(2x)

Step-by-step explanation:

The product formula can be used, along with the power rule.

d(uv) = du·v +u·dv

d(y^2/x) = d(18)

2y·dy/x -y^2/x^2·dx = 0

2x·dy -y·dx = 0 . . . . . . . . multiply by x^2/y

dy/dx = y/(2x) . . . . . . . . add y·dx, divide by 2x·dx

6 0

3 years ago

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

olga_2 [115]

Answer:

$7\pi cm^2$

Step-by-step explanation:

The area of a circle is given by $A=\pi r^2$

For circle B, the radius is 3 cm, it has an area of $\pi *3^2=9\pi cm^2$

Circle D also has a radius of 1 cm. Its area is $\pi *1^2=\pi cm^2$

Circle P also has a radius of 1 cm and area $\pi*1^2=\pi cm^2$

The area of the shaded region is then $9\pi -\pi-\pi=7\pi cm^2$

5 0

3 years ago

Given that LM and LN are tangent to the circle and that the measure of angle MLN = 75.86, find the measure of arc MN.

siniylev [52]

we know that

The measure of the external angle is the semidifference of the arcs that it covers

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

Let

x------> minor arc MN

major arc MN=360-x

substitute in the formula above

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x

x=104.14°

therefore

the answer is

the measure of arc MN (minor arc) is 104.14°

7 0

3 years ago