The correct answer is (c) It would have lower ionization energies than K and a lower electronegativity value than K
Explanation- The unknown element belongs to the alkali metals of periodic table. The alkali metal atoms have the largest size in a particular period of the period of periodic table. With the increase in the atomic number, the atom becomes larger.
Atomic radius decreases --> ionization energy increase---->Electronegativity increases. We can use this flow chart to compare the IE and EN of the element. As K have lower radii than the unknown element, so the IE and EN of K will be greater than the unknown element.
Answer:
The correct answer is -0.129 kJ
Explanation:
In the given case, the cooling of the balloon is done by withdrawing 0.784 J of heat, and the work done by the atmosphere on the balloon is 655 J. First, there is a need to transform kJ into J, 1 kJ = 1000 J. So, 0.784 kJ would be 784 J.
The ΔE or the change in the internal energy can be calculated by using the formula, ΔE = q + w ----- (1).
In the given case, q refers to the heat moved out of the system, that is, the value of q would be less than 0 or will be a negative quantity. Therefore, the heat moved out of the system will be -784 J. On the other hand, as the work or w is done on the system, therefore, the value of w would be more than 0 or will be a positive quantity. Thus, the value of w will be +655 J.
Now putting the values in the equation (1) we get,
ΔE = -784 J + 655 J
ΔE = -129 J or -0.129 kJ
As the change in internal energy comes out to be a negative value, therefore, the process is considered exothermic.
Answer:
compounds can be broken down to one another
Answer:
Explanation:
Hello!
In this case, since the molar mass of the empirical formula is:
Thus, the ratio of the molecular to the empirical formula is:
Thus, the molecular formula is six times the empirical formula:
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Transportation is the movement of food substances (sugars) from the stems to growing tissues and storage tissues.
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