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NISA [10]
3 years ago
14

The French Le Surete included an ex-criminal, Vidocq, who put together files describing the individual modus operendi, or the __

___, of each criminal.
criminal behaviors

fingerprints

home addresses

relatives who were also criminals
Chemistry
1 answer:
zmey [24]3 years ago
5 0

Answer:criminal behavior

Explanation:

Edge 2021

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In an experiment, a student was assigned to find the formula of an unknown hydrate that weighed 15.67g. The anhydrate, XCO3 (mol
meriva

Answer:

5.0 moles of water per one mole of anhydrate

Explanation:

To solve this question we must find the moles of the anhydrate. The difference in mass between the dry and the anhydrate gives the mass of water. Thus, we can find the moles of water and the moles of water per mole of anhydrate:

<em>Moles Anhydrate:</em>

7.58g  * (1mol / 84.32g) = 0.0899 moles XCO3

<em>Moles water:</em>

15.67g - 7.58g = 8.09g * (1mol / 18.01g) = 0.449 moles H2O

Moles of water per mole of anhydrate:

0.449 moles H2O / 0.0899 moles XCO3 =

5.0 moles of water per one mole of anhydrate

6 0
2 years ago
If there are many forces acting on an object how can the net force be 0
zysi [14]
You have to balance out those forces and apply the same amount of equal and opposite force to it. I hope I helped ^^
4 0
3 years ago
Please help I can't balance and Google isn't helping
DiKsa [7]
The first one is right and so is eight you have to add them together to see if they go together if they dont add what is missing
5 0
3 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi
insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

          E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}

                             = 0.535 - 1.065

                             = - 0.53 V

Also, it is known that relation between E^{o}_{cell} and K is as follows.

            E^{o}_{cell} = \frac{RT}{nF} \times ln K

                 ln K = \frac{nFE^{0}_{cell}}{RT}      

Substituting the given values into the above formula as follows.

                 ln K = \frac{nFE^{0}_{cell}}{RT}    

                        =  \frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}  

                ln K = -41.28

                    K = e^{-41.28}    

                        = 1 \times 10^{-18}

Thus, we can conclude that the value of the equilibrium constant for the given reaction is 1 \times 10^{-18}.      

5 0
3 years ago
How much is one liter
Bas_tet [7]

Answer:

1 litre = 1000 millilitres

8 0
3 years ago
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