Question

A 2.3 L gas bubble at STP is heated to 984 K, and the pressure increases to 1520 mmHg. What is the new volume?

Answer 1

The new volume of the gas bubble as its temperature is heated to the given value and pressure increased is 4.14L.

Combined gas law

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

• Initial volume of the gas V₁ = 2.3L

at STP

• Initial pressure P₁ = 1.0atm

• Initial temperature T₁ = 273.15K
• Final temperature T₂ = 984K

• Final pressure P₂ = 1520mmHg = 2.0atm

• Final volume V₂ = ?

To calculate the new volume the gas, we subtsitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

P₁V₁T₂ = P₂V₂T₁

V₂ = P₁V₁T₂ / P₂T₁

V₂ = ( 1.0atm × 2.3L × 984K ) / ( 2.0atm × 273.15K )

V₂ = 2263.2LatmK / 546.3atmK

V₂ = 4.14L

Therefore, the new volume of the gas bubble as its temperature is heated to the given value and pressure increased is 4.14L.

Learn more about the combined gas law here: brainly.com/question/25944795