A <span>heating curve having horizontal plateaus at certain points during the heating process means that the process occurs at increase heating. </span>
Answer:
85.5 mmHg is the pressure of the gas sample when the valve is opened.
Explanation:
The combined gas equation is,
where,
= initial pressure of gas in container A = 165 mmHg
= final pressure of gas = ?
= initial volume of gas in container A= 
= final volume of gas = 135 mL + 117 mL = 252 mL
= initial temperature of gas in container A = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
85.5 mmHg is the pressure of the gas sample when the valve is opened.
Answer:
mole fraction hexane 0.64
Explanation:
We know from Raoult's law of partial pressures that for a binary mixture, the vapor pressure above solution is the sum of the partial pressures of each gas:
P total = P(A) + P(B)
Also the partial pressure of a component is the product of its mole fraction , X, times its pure vapor pressure:
Ptotal = X (A)Pº(A) + X (B)Pº(B)
Since for solution of two components the mole fractions add to one, we now have all the information required to compute the answer.
250 torr = X(hexane)151 torr + ( 1 - X(hexane) )425 torr
250 = 151X(hexane) + 425 - 425 X(hexane)
274 X(hexane) = 175
X(hexane) = 1 -0.6 = 0.64
The answer is 341.7 g.
(1) Calculate the molar mass (M) of CaCl2 which is the sum of atomic masses (A) of elements:
M(CaCl2) = A(Ca) + 2A(Cl)
A(Ca) = 40.1 g/mol
A(Cl) = 35.45 g/mol
M(CaCl2) = 40.1 + 2 * 35.45 = 40.1 + 70.9 = 111 g/mol
(2) Calculate in how many moles are 535 g:
M(CaCl2) = 111 g/mol
111g : 1mol = 535 g : xmol
x = 535 g * 1mol : 111g = 4.82 mol
(3) Calculate how many grams of Cl are in 4.82 mol:
A(Cl) = 35.45 g/mol
2A(Cl) = 2 * 35.45 = 70.9 g/mol
70.9 g : 1 mol = x : 4.82 mol
x = 70.9 g * 4.82 mol : 1 mol = 341.7 g
The required volume of 0.10M NaOH solution that student will add is 20 mL.
<h3>How do we calculate the volume?</h3>
Volume of any solution which is required to prepare buffer will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of NaOH solution.
- M₂ & V₂ are the molarity and volume of HF solution.
On putting values, we get
V₁ = (0.1)(20) / (0.1) = 20mL
Hence required volume of NaOH solution is 20mL.
To know more about molarity & volume, visit the below link:
brainly.com/question/24305514
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