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andrew-mc [135]
3 years ago
7

Please help I will give out brainliest I have done the first one already.

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

In drawing an elevation drawing, there are four or five views of the sides of an object which may be displayed including the front, rear,  and sides of the object

The elevation drawing is a scaled horizontal orthographic projection showing one side of an object to  a plane vertical parallel to the object's sides so as to depict the appearance of the completed object appearance

The required elevation is included in the attached diagram

Step-by-step explanation:

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Maya made $324 for 18 hours of work. At the same rate how many hours would she have to work to make $126
Illusion [34]

Answer:7

Step-by-step explanation:

324/18 hours = 18$ per hour

126/18$=7 hours

4 0
3 years ago
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I need to answer a question.
Lady_Fox [76]

Answer:

17/20

Step-by-step explanation:

Probability is actually very fun once you understand it. So, you know that the bag contains 20 marbles. You also know that only 3 of those 20 are yellow. Subtract 3 from 20 and you get 17, which is your answer. Hope this helped, and let me know if you need any more help!

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
4 years ago
How long will the other side be ?
Sergio039 [100]

Answer:

Step84-by-step explanation:

if it means 92-8 then its 84 but otherwise look at your class notes

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