Please help I will give out brainliest I have done the first one already.
1 answer:
Answer:
In drawing an elevation drawing, there are four or five views of the sides of an object which may be displayed including the front, rear, and sides of the object
The elevation drawing is a scaled horizontal orthographic projection showing one side of an object to a plane vertical parallel to the object's sides so as to depict the appearance of the completed object appearance
The required elevation is included in the attached diagram
Step-by-step explanation:
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Answer:
If we compare the p value and the significance level assumed of 0.05 we see that so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly higher than 0.26^2=0.0676.
Step-by-step explanation:
Notation and previous concepts
A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"
represent the sample size
represent the confidence level
represent the sample variance obtained
represent the value that we want to test
Null and alternative hypothesis
On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:
Null Hypothesis:
Alternative hypothesis:
Calculate the statistic
For this test we can use the following statistic:
And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.
Calculate the p value
In order to calculate the p value we need to have in count the degrees of freedom , on this case df=15-1=14. And since is a right tailed test the p value would be given by:
In order to find the p value we can use the following code in excel:
"=1-CHISQ.DIST(31.5,14,TRUE)"
Conclusion
If we compare the p value and the significance level assumed of 0.05 we see that so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly higher than 0.26^2=0.0676.
You can solve for x and y in terms of z, then let z take on the value of the parameter.
Subtracting the first equation from the second, you get
... x_2 +x_3 = 1
Subtracting that from the first equation gives you
... x_1 +2x_3 = 3
Let x_3 = t. Then your parametric equations are ...