So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400
Help!! I need help with my math!!
2 answers:
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Answer:
S'(t) = 0.09t^2 + t + 9
S(2) = 24.24
S'(2) = 11.36
S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.
S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month
Step-by-step explanation:
The derivate of the sales function S'(t) , which is the rate at which sales vary with time in months, is:
S(2) is found by applying t=2 to S(t):
S'(2) is found by applying t=2 to S'(t):
Since the sales function gives the amount of sales in millions of dollars,
S(11) = 203.43 means that the sales of the company 11 months from now is $203,430,000.
S'(t) represents the rate of change in sales in millions of dollars per month.
S'(11) = 30.89 means that, 11 months from now, the rate at which sales change is $30,890,000 per month