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Evgesh-ka [11]
3 years ago
10

Use the Law of Cosines to find the missing angle. Find m∠A to the nearest tenth of a degree.

Mathematics
2 answers:
Savatey [412]3 years ago
8 0

Firstly, we can look at our givens,

a = 17

b = 22

c = 30

And we are looking for m∠A

a^2=b^2 +c^2 -2bc (cosA) Is the Law of Cosines. Now we can solve for our unknown, m∠A. This will give us

A = cos^{-1} (\frac{-a^2+b^2+c^2}{2bc})

Now we can substitute in our given variables.

A= cos^{-1} (\frac{-(17^2)+27^2+30^2}{2(27)(30)} )

Then we can plug this into our calculator which will give us

34.19185257 degrees

Now we just have to round to the nearest tenth

This means that the answer is 34.2 degrees

NemiM [27]3 years ago
5 0

For this case we have:

In the attached image, we state the law of cosine at the beginning. Then, the angle that you want to find is identified. Once the angle is identified, the formula of the corresponding side is chosen.

The data is replaced and the required angle is cleared following the steps of the attached image.

Answer:

33.9 degrees

See attached image

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Answer:

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Step-by-step explanation:

x-intercept when y = 0

-6x + 0 = 8

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-6x = 8

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x = -4/3

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4 years ago
Solve for k: -2k = k - 7 - 8 and explain in number form
Kamila [148]

Answer:

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Hope this helps!

7 0
3 years ago
Finding the expression
vekshin1
If you combine like terrms its easy, you just have to -5+5+6y, 6y=16 y=2.66666667
4 0
4 years ago
Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

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Read 2 more answers
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