I hope this helps you
35/91
5.7/13.7
5/13
The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:

- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em />
<em> ------ 1/6 full</em>
<em />
<em> --- baseballs added</em>
<em />
<em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:

So, we have:

The number of baseballs it can hold is calculated as follows:

Multiply through by 6

Collect like terms


Divide through by 3

Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
brainly.com/question/20337104
Well, we can input both variables to check and see if the numbers hold.
-691 = -51(-15) - 74
-691 = 765-64
-691 = 701
(-15, -691) does not make the equation true.
The Answer is <u>A. 3. :D</u>
Answer:
D.
Step-by-step explanation:
the graph has a y intercept of -3
try substituting any point in one of the equations that fit the graph in this one that is D.
try(1,1)
1<1-3
1<-3
it is false so shade the outside of the graph
hope it helps