Question

10. An archery arrow is shot with a speed of 45 m/s at an angle of 10°. How for

Answer 1

Answer:

The horizontal distance travelled by an arrow is  70.6  m.

Step-by-step explanation:

Given : An archery arrow is shot with a speed of 45 m/s at an angle of 10°.

To find : How for  horizontally can the arrow travel before hitting a target at the same height  from which it was released?

Solution :

The expression for the range of the projectile motion is

$R=\frac{V^2\sin 2\theta}{g}$

Where, the velocity of an arrow is V = 45 m / s

The angle of release of an arrow is  $\theta=10^\circ$

The acceleration due to gravity is g =9.81  m/s²

Substitute the values,

$R=\frac{45^2\sin 2(10)}{9.81}$

$R=\frac{2025\sin (20)}{9.81}$

$R=70.6\ m$

Therefore, the horizontal distance travelled by an arrow is  70.6  m.