Max weight of the crate - the empty crate/ by 35 (the weight of the individual boxes)
850-150=700
700 lbs is the remaining weight available that can be filled with 35 lb boxes, to find out the number of boxes that can be added to the crate, divide 700 by 35.
700/35 = 20
Ernest can put in 20 boxes in the crate.
this woulld be your answer
0.526315789473684
2y + 3.....when y = 4
2(4) + 3 =
8 + 3 =
11 <==
Answer:
Step-by-step explanation:
Let the length of one side of the square base be x
Let the height of the box by y
Volume of the box V = x²y
Since the box is opened at the top, the total surface area S = x² + 2xy + 2xy
S = x² + 4xy
Given
S = 7500sq in.
Substitute into the formula for calculating the total surface area
7500 = x² + 4xy
Make y the subject of the formula;
7500 - x² = 4xy
y = (7500-x²)/4x
Since V = x²y
V = x² (7500-x²)/4x
V = x(7500-x²)/4
V = 1/4(7500x-x³)
For us to maximize the volume, then dV/dx = 0
dV/dx = 1/4(7500-3x²)
1/4(7500-3x²) = 0
(7500-3x²) = 0
7500 = 3x²
x² = 7500/3
x² = 2500
x = √2500
x = 50in
Since y = (7500-x²)/4x
y = 7500-2500/4(50)
y = 5000/200
y = 25in
Hence the dimensions of the box that will maximize its volume is 50in by 50in by 25in.
The Volume of the box V = 50²*25
V = 2500*25
V= 62,500in³
Hence the maximum volume is 62,500in³
ANSWER
Yes
No
No
Yes
EXPLANATION
The given line passes through the points,.
We need to determine the slope of this line using these two points.
The formula for finding the slope is
We can now use the formula
in the slope intercept form.
If we use the point
the equation will be,
If we use the point,
we obtain,
