We need to compute the diagonal of yhe square.
d²=7²+7²=49×2cm²
d=7×sqrt(2)=7×1.41=9.87cm.
The diagonal we just computed is the diameter of the circle that contains the square.
Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.
Answer:
The weight is 4 pounds :D
Step-by-step explanation:
Answer:
x = -40
Step-by-step explanation:
First we distribute
5x + 35 + 2 = 4x - 4 + 1
Collect like terms
5x + 37 = 4x - 3
Subtract 37 from both sides
5x = 4x - 40
Subtract 4x from both sides
1x = -40 OR x = -40
Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer isthe abscissa of the midpoint of the line segment is 3√2
see the attached figure