Answer:
0.3891 = 38.91% probability that only one is a second
Step-by-step explanation:
For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
17% of its goblets have cosmetic flaws and must be classified as "seconds."
This means that
Among seven randomly selected goblets, how likely is it that only one is a second
This is P(X = 1) when n = 7. So
0.3891 = 38.91% probability that only one is a second
First you have to find 1/3 of the marbles. That means in the twelve marvels she has, there are three even groups. Divide twelve by three and you get four. So if each group is four, it is simple from here on out. If she started out with twelve and she lost 1/3 of them(4) it would be 12-4. You know this because lost is another for for subtract. 12-4=8. She has 8 marbles left.
Answer:
x=45
Step-by-step explanation:
Then,
x/5(15)-47=28
Step 1: Simplify the equation on both sides
x/9(15)-47=28
5/3x-47=28
Step 2: Add 47 to both sides
5/3x-47+47=28+47
5/3x=75
Step 3: Multiply both sides by 3/5
(3/5)*(5/3x)=(3/5)*(75)
x=45