5+4^2÷2 simplified with work shown

Can anybody help me figure out the area of simple composite figure?

zvonat [6]

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

$A=A_{1} +A_{2}$

where,

$A$ be the area of the given figure

$A_{1}$ be the area of the rectangle

$A_{2}$ be the area of the semicircle.

The area of the rectangle = $lb$ where, l be the length and b be the width
Area of the semicircle = $\frac{1}{2} \pi r^{2}$ , r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

$A_{1} = (16)(12)$ sq ft

or, $A_{1} = 192$ sq ft

$A_{2} = \frac{1}{2} (3.14)(6^{2} )$ sq ft

or, $A_{2}=56.52$ sq ft

So,

$A = 56.52+192$ sq ft

$A$ = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

Hence,

The area of the composite figure is 248.5 sq ft.

7 0

3 years ago

On April 1, the price of gas at Bob's Corner Station was $3.35 per gallon. On May 1, the price was $3.85 per gallon. On June 1,

Zina [86]

<h2>Answer:</h2>

1. Between April 1 and May 1, Bob's price incrdased by <u>$0.50 or 15%</u>.

2. Between May 1 and June 1, Bob's price decreased by <u>$0.50 or 13%</u>.

3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is <u>$0.1 more expensive</u> when gas costs $3.85 than when gas costs $3.35.

4. Suppose the Fed raises the target for the federal fundsb rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately <u>0.25%</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Between April 1 and May 1, Bob's price incrdased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

$C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.35} =0.15$ =15%.

<h3>2. Between May 1 and June 1, Bob's price decreased by...</h3>

<em>Take the difference of the prices to find an absolute value:</em>

$3.85 - $3.35= $0.50.

<em>Use the following formula to find the relative value:</em>

C= |Original value - New value|/ Original value

$C=\frac{|OV-NV|}{OV}=\frac{|3.35-3.85|}{3.85} =0.13$ =13%.

<h3>3. Suppose that atgas station across the street, prices are always 20% higher than Bob's. In absolute dollar terms, the difference between Bob's prices and the prices across the street is (blank) when gas costs $3.85 than when gas costs $3.35.</h3>

<em>In this question we are looking for the difference of a difference. </em>

<em>If the proces across the street are always 20% higher, to find how much the gallon costs just multiply the price by 1.20, to increase 0.2 or 20%:</em>

$3.85 * 1.20= $4.62.

<em>Now, to see how much expensive this price is compared to Bob's, take de difference between the prices:</em>

$4.62 - $3.85= $0.77.

<em>Do the same to find the difference between the gas prices when the price is $3.35.</em>

$3.35 * 1.20= $4.02.

$4.02 - $3.35= $0.67.

Now, find the difference of those differences:

$0.77 - $0.67= $0.1.

<h3>4. Suppose the Fed raises the target for the federal funds rate from 2% to 2.25%. This change of percentage points means that the Fed raised its target by approximately (blank).</h3>

<em>Find the difference between percentages:</em>

2.25% - 2%= 0.0225 - 0.02= 0.0025= 0.25%.

<em>Simpler method:</em>

2.25% - 2%= 0.25%.

3 0

2 years ago

Which equation represents the relationship shown in the table?

jeka94

Answer:

y=x+1.5

Step-by-step explanation:

Y is always 1.5 more than x.