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Olenka [21]
3 years ago
15

This is algebra, if you can help that is appreciated.

Mathematics
2 answers:
BARSIC [14]3 years ago
6 0

Answer:

b

Step-by-step explanation:

sweet [91]3 years ago
5 0

Answer

B

Step-by-step explanation:

because it has to be less than according to the word problem and using common sense I know that if there are more than 1 of a number as an answer choice that means that it is most likely the answer

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The sum of 7 and the quotient of a number X and 8
Mariulka [41]
7 + 8x. Hope it helps!
5 0
3 years ago
Find the smallest number in 9375*that will replace *so as to make it divisible by 8
german

3 would turn to 2

cause it can be dividable by 8

6 0
4 years ago
The subject of the formula below is y<br> y=x-5<br> rearrange the formula to make x the subject
NeX [460]

Answer: x=y+5

Step-by-step explanation:

Add 5 to both sides:

y+5=x-5+5

y+5=x

3 0
3 years ago
The vertex of this parabola is at (-2,-3). When the y-value is -2 the x-value is -5. What is the coefficient of the square term
olchik [2.2K]

Answer:

a = -3

Step-by-step explanation:

You're correct.

The form of the equation you need is

x=a(y-k)^2+h

Filling in our h, k, y, and x:

-5=a(-2+3)^2-2 which simplifies to

-5=a(1)-2 which simplifies further to

a=-3

Very good!!!! These can be tricky, but you got it!!

4 0
3 years ago
A data set includes 106 body temperatures of healthy adult humans having a mean of 98.7degreesF and a standard deviation of 0.66
blondinia [14]

Answer:

The 99% confidence intervals are

(98.4346 , 98.7654)

C) This suggests that the mean body temperature could very possibly be 98.6degrees°F.

<u>Step-by-step explanation:</u>

Given data a data set includes 106 body temperatures of healthy adult humans having a mean of 98.7degreesF and a standard deviation of 0.66degreesF

sample size n = 106

Mean of the population   ' μ' = 98.7degreesF

standard deviation of population 'σ' = 0.66degreesF

Mean of the sample x⁻ = 98.6degreesF

Level of significance ∝ = 0.99 0r 0.01

<u>Confidence limits :-</u>

The values (x^{-} - 2.58\frac{S.D}{\sqrt{n} } ,x^{-} +2.58\frac{S.D}{\sqrt{n} } ) are called 99% of confidence limits

For the mean of the Population corresponding to the given sample.

(98.6 - 2.58\frac{0.66}{\sqrt{106} } ,98.6 +2.58\frac{0.66}{\sqrt{106} } )

on calculation, we get

(98.6 - 0.1654,98.6 + 0.1654)

The 99% confidence intervals are

(98.4346 , 98.7654)

C)<u> This suggests that the mean body temperature could very possibly be 98.6degrees°F</u>.

3 0
3 years ago
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