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GalinKa [24]
3 years ago
8

Pa Evaluate when p=5 and q =13. p+a

Mathematics
1 answer:
Ivenika [448]3 years ago
4 0
The answer is 18 just add them
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I’m not very good at these so someone help me out :,)
Lilit [14]

Answer:

-4,-1

i have to put 20 character so here is 20 characters

6 0
3 years ago
Read 2 more answers
A rectangle is 40 yards long and 30 yards wide. What is the length of the diagonal that cuts through the center?
choli [55]

Answer:

it should be 50

Step-by-step explanation:

Using the pythagorean theorem c = \sqrt{a^{2} +b^{2} } we get 50

4 0
3 years ago
The volume of a cone of radius r and height h is given by V=πr²h³. If the radius and the height both increase at a constant rate
Aloiza [94]

Answer:

The volume of cone is increasing at a rate 1808.64 cubic cm per second.

Step-by-step explanation:

We are given the following in the question:

\dfrac{dr}{dt} = 12\text{ cm per sec}\\\\\dfrac{dh}{dt} = 12\text{ cm per sec}

Volume of cone =

V = \dfrac{1}{3}\pi r^2 h

where r is the radius and h is the height of the cone.

Instant height = 9 cm

Instant radius = 6 cm

Rate of change of volume =

\dfrac{dV}{dt} = \dfrac{d}{dt}(\dfrac{1}{3}\pi r^2 h)\\\\\dfrac{dV}{dt} = \dfrac{\pi}{3}(2r\dfrac{dr}{dt}h + r^2\dfrac{dh}{dt})

Putting values, we get,

\dfrac{dV}{dt} = \dfrac{\pi}{3}(2(6)(12)(9) + (6)^2(12))\\\\\dfrac{dV}{dt} =1808.64\text{ cubic cm per second}

Thus, the volume of cone is increasing at a rate 1808.64 cubic cm per second.

5 0
3 years ago
Solve for t.<br> - 9r +5 &lt;17<br> AND 132 + 25 &lt;-1
Deffense [45]

Answer:

1.) r>-3/4 and 2.) 157<-1

3 0
3 years ago
Brittany was tracking the increasing temperature in the morning. At 8 a.m., it was 68 degrees Fahrenheit. At 10 a.m., it was 74
AysviL [449]
Im gonna go with A..
4 0
3 years ago
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