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ZanzabumX [31]
3 years ago
10

When would it be beneficial to make a copy of a document

Computers and Technology
1 answer:
aksik [14]3 years ago
3 0

Answer:

When you need to keep the original document or send the document to multiple people.

Explanation:

If you need to keep the original document (eg. marriage documents or birth certificate or something important), you would make a copy of it (unless you are sending it to a lawyer or a government agency).

If you, for instance, have a memo for your company that all your employees need to read, you would copy the document so you would be able to print it and send it to everyone without passing the document one at a time.

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Write a program that creates a linked list object of 10 characters and creates a second list object containing a copy of the fir
slamgirl [31]

Answer:

Below code is in c++ with explanation.

Explanation:

Explanation is in comment format, any line starting with //.

#include <iostream>

#include <cstdlib>

using namespace std;

//creating a Node struct which holds node data

struct Node {  

  char data;  

  struct Node *next;  

};  

//creating variable of Node as head

// this head is the start point of ordered Linked list

struct Node* head = NULL;    

// This method is used to insert new value in node

void insert(char new_data) {  

// allocating the memory for new node

  struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));  

// assigning the data to new node

  new_node->data = new_data;  

// If head == null then it means we are inserting first value

// it will return after creating first node and assign it to

// head as head is the entry point

  if(head == NULL){

    new_node->next=NULL;

   head=new_node;

    return;

  }

// Now we need to treverse to end of linked list

// that's why creating a lastNode variable  

// As we don't want our head to point any other node

// except first node

  Node* lastNode = head;

  while(lastNode->next != NULL){

   lastNode=lastNode->next;

  }

// as last node next will be null to end the traversing  

// on linked list

  new_node->next= NULL;

// assigning last node to its previous node  

  lastNode->next = new_node;  

   

}  

// This variable will hold the first node for reverse linklist

struct Node* reverseHead = NULL;    

// This method will reverse the ordered linklist

void reversLinkList(){

  Node* lastNode = head;

// traversing the ordered linklist

  while(lastNode!= NULL){

// creating new linked list

   struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));  

   new_node->data = lastNode->data;  

   new_node->next = reverseHead;  

   reverseHead = new_node;  

   lastNode = lastNode->next;

  }

   

}

// display method will travers the linklist that

// was passed throw paramter

void display(Node* node) {  

  struct Node* ptr;

  ptr = node;

  while (ptr != NULL) {  

     cout<< ptr->data <<" ";  

     ptr = ptr->next;  

  }  

}  

// main method is the entry point of this program

int main() {  

// adding 10 nodes by calling insert method

  insert('a');

  insert('b');

  insert('c');

  insert('d');

  insert('e');

  insert('f');

  insert('g');

  insert('h');

  insert('i');

  insert('j');

  cout<<"The Ordered linked list is: ";

// calling display method with head to print ordered linklist

  display(head);  

  cout<<endl;

  cout<<"The Reversed linked list is: ";

// calling reversLinkList to reverse the ordered linklist

  reversLinkList();

// calling display method with reverseHead to display  

// reversed linklist

  display(reverseHead);

   

  return 0;  

}

4 0
3 years ago
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