Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
Answer:
c
Step-by-step explanation:
For this question you can say d = 15 feet so we need the t then you can say :
15 = l 130 - 25t l ⇒ because of the absolute value you should say :
1) 130 - 25t = 15 ⇒ -25t = 15 - 130 ⇒ - 25t = -115 ⇒ t = 115/25 = 4.6 sec
2) 130 - 25t = - 15 ⇒ -25t = -15 - 130 ⇒ -25t = - 145 ⇒ t = 145/25 = 5.8 sec
so the answer is c :))
i hope this is helpful
V = (4/3)×3.14×(1.5^3)
V = 14.1 in^3
G:{3,4,6}->{0,9}
The pairs represent the input (first number in each pair) and the result (second nu.ber in each pair) for the relation G. for example G(3)=9.
The domain is the set of values that the relation can act upon. The range is the set of the values the results can take
Answer:
Step-by-step explanation:
At first,
Let start writing the squares of number 0 to 10,
0²=0
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
Now,
According to your question,
- The two numbers should be square numbers
- They should be greater than 1.
- Their sum should be 100.
Hence, your given conditions matches with the numbers 64 and 36.
Therefore, the numbers are 64 and 36.
- 64 and 36 are greater than 1.
- 64 is a square of 8 and 36 is the square of 6.
- 64+36=100
