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AleksandrR [38]
3 years ago
12

What is the image of point (2,8) for mapping (x,y), (x-8,y+1)

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0
To translate this point, we need to subtract 8 from the x-value and add 1 to the y-value

2-8=-6
8+1=9

So the new point is (-6,9)

Hope this helps
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Find the unknown. = (65 × 3) + 9
alekssr [168]

Answer:

204

Step-by-step explanation:

Following the order of operations, what is within the parenthesis is solved first.

<em>65 x 3 = 195</em>

Then, you add 9 to 195.

<em>195 + 9 = 204</em>

<em>204</em> is the final answer.

Have a nice day! ^-^

5 0
3 years ago
Manuel created a factor tree and wrote the prime factorization of 60 shown below.
bagirrra123 [75]

Answer:

The second one or B- "He did not find the prime factors of 4."

Step-by-step explanation:

I got it right on Edge2020

7 0
2 years ago
Read 2 more answers
14 = 6x4+b <br><br> I WILL MARK BRAINLYIEST FOR 1ST PERSON
Ira Lisetskai [31]
14 = 6x4 + b
14 = 24 + b
-10 = b

Hope this is accurate & helpful! Let me know if there are any errors or if you have any additional questions.
7 0
1 year ago
3(c-4)=4(c-6)<br> i don't know how to solve it, either
STatiana [176]

Answer:

c = 12

Step-by-step explanation:

3(c - 4) = 4(c - 6)

Use the distributive property on each side.

3c - 12 = 4c - 24

Now you need the terms with c on the left side and the numbers on the right side. Subtract 4c from both sides. Add 12 to both sides.

3c - 4c - 12 + 12 = 4c - 4c - 24 + 12

Combine like terms on each side.

-c = -12

Multiply both sides by -1.

c = 12

4 0
2 years ago
Read 2 more answers
A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d
nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

P(t)=Ce^{kt}

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

P(t)=Ce^{kt}

For t=0, we have:

P(0)=Ce^0=C=58

If we use the duplication time, we have:

P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08

Then, we have the model as:

P(t)=58e^{2.08t}

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644

The rate of growth can be calculated as dP/dt and is:

dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)

For t=8, the rate of growth is:

dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81

3 0
3 years ago
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