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Debora [2.8K]
3 years ago
12

Either answer with explanation or give me the length from 0 to C with explanation please.

Mathematics
1 answer:
muminat3 years ago
3 0
Check the picture below.

a circle has a total of 360°, if we split the circle with a hexagon's radii, each radii with their vertices will make an equilateral triangle who will have three 60° angles.  Anyhow, if we run a line like the apothem "a" there, we'll end up with a 30-60-90 triangle, and then we can apply the 30-60-90 rule, as you see there.

since we know then that the distance from a vertex at the base to the center is 2, and the slant-height, sticking out from that vertex, is 6, then we can use the pythagorean theorem as you see in the picture, to get the distance V.

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Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے
Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

A=\frac{8}{3} \sqrt{p h} \cdot h

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\

Generally, the equation for the Area is mathematically given as

& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\

&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h

A=\frac{8}{3} \sqrt{p h} \cdot h

In conclusion,  the equation for the Area is

   

A=\frac{8}{3} \sqrt{p h} \cdot h

Read more about Area

brainly.com/question/27683633

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1 year ago
FIRST ONE TO ANSWER GETS FREE 100 POINTSSSSSS and brainliest
ANEK [815]

Answer:

ok thanks bro lol thanks

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66.27 is your answer
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A bookkeeper bought 2,000 exercise book distributed 200 books to the student from poor economic background as donation .he sold
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Books left=2000-200=1800

ATQ

\\ \sf\longmapsto 1800x+10=0.08x

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\\ \sf\longmapsto x(1800-0.08)=-10

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\\ \sf\longmapsto x=0.005

Now

\\ \sf\longmapsto CP=0.005(2000)=10

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