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4 years ago

State a true Conclusion

Mathematics

2 answers:

Maru [420]4 years ago

4 0

Then Zela lives in Zee.

Irina-Kira [14]4 years ago

3 0

<h2>Answer:</h2>

The conclusion that can be drawn with the help of these statements is:

Zela lives in Zee.

<h2>Step-by-step explanation:</h2>

We are given statement as:

1) If people live in Zook, then they live in Zee.

2) Zela lives in Zook.

Since we know that if we are given a statement like:

If p then q

and some element belong to p then it belong to q as well.

Here we have:

p: People live in Zook.

q: They live in Zee.

and we are given that Zela live in Zook.

Hence, the true conclusion will be:

Zela lives in Zee.

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3 years ago

Marcus and his family are planning a vacation that involves horseback riding. Horseshoe ranch charges a $12.95 ranch entrance fe

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The equation that models the scenario is y = 12.95 + 14.95x

<h3>How to determine the linear equation?</h3>

The given parameters are:

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Represent the number of houses with x, and the total charge with y

So, we have:

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2 years ago

Show that (x+y)² − (x −y)² = 4xy for all real numbers x and y.

nata0808 [166]

To show: (x+y)² − (x −y)² = 4xy

Using difference of square identity:

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Taking left side

$\Rightarrow (x+y)^2-(x-y)^2$

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3 years ago

A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he

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Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

$h(t) = -16t^2 + 30t$

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

$f(x) = ax^2 + bx + c$ :

$f(\frac{-b}{2a}) = maximum/minimum$

i.e we first solve for $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for x in $f(x) = ax^2 + bx + c$

In our case:

First we need to solve $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for t in $h(t) = -16t^2 + 30t$

By comparison:

$b = 30$

$c = -16$

$\frac{-b}{2a} = \frac{-30}{2 * -16}$

$\frac{-b}{2a} = \frac{-30}{-32}$

$\frac{-b}{2a} = \frac{30}{32}$

$\frac{-b}{2a} = \frac{15}{16}$

Substitute $\frac{15}{16}$ for t in $h(t) = -16t^2 + 30t$

$h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})$

$h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}$

$h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}$

$h(\frac{15}{16}) = \frac{-225 + 450}{16}$

$h(\frac{15}{16}) = \frac{225}{16}$

$h(\frac{15}{16}) = 14.0625$

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because $14.0625 < 15$

8 0

3 years ago

Please help! I need it correctly please!! I can't fail this lesson.

DIA [1.3K]

Answer:

The method is to multiply the numbers by there varible

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers