All categories

3 years ago

You invest $15,000 in a savings account with an annual interest rate of 2.5% in

Mathematics

1 answer:

almond37 [142]3 years ago

5 0

Answer:

$\$16,990.62$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=5\ years\\ P=\$15,000\\ r=2.5\%=2.5/100=0.025\\n=4$

substitute in the formula above

$A=15,000(1+\frac{0.025}{4})^{4*5}$

$A=15,000(1.00625)^{20}$

$A=\$16,990.62$

You might be interested in

7x2 - 2x2 = .......................................

natulia [17]

Answer:

Step-by-step explanation:

7*2 - 2*2 = 14 - 4 = 10

Plz mark as brainliest!

4 0

3 years ago

Read 2 more answers

Help me please ASAP

Oliga [24]

Answer:

Step-by-step explanation:

if im reading the qestuion right

so she had 80 bucks she spend 20 on a ticked so she has 60 left so if im reading it right she spent all of her money so 60 divde by 2 is 30.

hoped this helped!

3 0

3 years ago

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with

AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = $\left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]$

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0

3 years ago

A line that passes through (-8,4) and has a slope of -5/4

zhannawk [14.2K]

Answer:

y2-y1, x2-x1

Step-by-step explanation:

4-(-5)= 4-(-8)

4+5=4+8

9=12

9/12

3/4

the slope of line is 3/4

3 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago