Question

Please solve itI need to submit this by tomorrow ​

Answer 1

Answer:

1

Step-by-step explanation:

$(3^{n-1})\cdot(3^{1-n})\\\\=3^{n-1+1-n}\\\\\longrightarrow n-1+1-n=(n-n)+(-1+1)=0+0=0\\\\=3^{0}\\\\=1$