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liraira [26]
3 years ago
7

A rectangular prism has dimensions 3.2 in. by 5 in. by 1.5in. what is the volume area of the prism?

Mathematics
2 answers:
morpeh [17]3 years ago
8 0

Answer:

24

Step-by-step explanation:

3.2x5 x1.5=24

Hope this helps :)

Stells [14]3 years ago
3 0
It’s 24 because 3.2 x 5 x 1.5 = 24

It’s easy
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Ariana is shipping 8 bags of granola to a customer. Each bag weighs 22 ounces and the maximum weight she can ship in one box is
Anuta_ua [19.1K]

Ariana cannot ship all the bags in one box.

Ariana will be sending 8 bags which will weigh a total of:

= 22 ounces x 8

= 176 ounces

You need to convert this to pounds to see if it will fit in the box:

<em>1 pound = 16 ounces </em>

176 ounces in pounds is therefore:

= 176 / 16

= 11 pounds

The box can only take 10 pounds and 5 ounces which is less than the 11 pounds the bags weigh.

Ariana cannot ship all the bags in one box.

<em>Find out more at brainly.com/question/19990206.</em>

5 0
3 years ago
Ava is buying paint from Amazon. Ava
irina [24]

Answer:

2.625 cups or 21 ounces

Step-by-step explanation:

Ava needs 3/4 cup of blue paint for every 1 cup of white paint. So, the ratio is 0.75 : 1.

She has 28 ounces of white paint. But, you have to convert ounces to cups.

1 cup = 8 ounces

28 ounces ÷ 8 ounces/cup = 3.5 cups

Now set up a ratio.

\frac{0.75}{1} = \frac{x}{3.5}

X (how much blue paint is needed) is over 3.5 cups (the amount of white paint she has)

Cross multiply and divide.

\frac{0.75}{1} = \frac{x}{3.5}

x = 0.75 × 3.5

x = 2.625 cups

To convert to ounces, multiply by 8.

2.625 cups × 8 ounces = 21 ounces

Therefore, Ava needs 2.625 cups or 21 ounces of blue paint.

Hope that helps.

5 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
Which set of coordinates satisfies the equations 3x - 2y =15 and 4x - y = 20
babymother [125]

You use elimination the get x=5 and then plug it in to get y=0 so the coordinate is (5,0)

4 0
3 years ago
What is the value of this -3 2/3 ÷ 1/3​
mihalych1998 [28]

Answer:

-11

Step-by-step explanation:

Convert -3 2/3 to -11/3

-11/3÷1/3

Dividing by 1/3 is the same as multipling by 3

so the equation becomes

(-11/3)(3)

=-11

8 0
3 years ago
Read 2 more answers
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