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3 years ago

A rectangular prism has dimensions 3.2 in. by 5 in. by 1.5in. what is the volume area of the prism?

Mathematics

2 answers:

morpeh [17]3 years ago

8 0

Answer:

Step-by-step explanation:

3.2x5 x1.5=24

Hope this helps :)

Stells [14]3 years ago

3 0

It’s 24 because 3.2 x 5 x 1.5 = 24

It’s easy

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on Monday Steven read 9 pages of his new book to finish this first chapter on Tuesday he needs to read double of number of pages

Grace [21]

18

9*2
You just basically do 9 doubled which is 18

7 0

3 years ago

Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago

A regular octagonal pyramid has a base edge of 3m and a lateral area of 60m^2. Find its slant height.

Olin [163]

Octagon = 8-side polygon

<u>Find area of 1 triangle:</u>
Area of one side triangle = 60 ÷ 8 = 7.5 m²

<u>Given area and length, find height:</u>
Area of each triangle = 7.6 m²
Length of each triangle = 3m

Area = 1/2 x base x height
7.5 = 1/2 x 3 x height
Heigth = 5m

Answer: Slanted Height = 5 m

4 0

3 years ago

What is the length of QR?

Elena L [17]

Answer:

Step-by-step explanation:

Since the triangle is right with hypotenuse QR

Use Pythagoras' identity to solve for QR

The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

QR² = 8² + (8 $\sqrt{3}$ )²