Question

Cyclopropane, C3H6, is used as a general anesthetic. If a sample of cyclopropane stored in a 2.36-L container at 10.0 atm and 25.0°C is transferred to a 7.79-L container at 5.56 atm, what is the resulting temperature? Enter your answer in the provided box

Answer 1

Explanation:

The given data is as follows.

     $V_{1}$ = 2.36 L,    $T_{1}$ = $25^{o}C$ = (25 + 273) K = 298 K,

      $P_{1}$ = 10.0 atm,   $V_{2}$ = 7.79 L,

       $T_{2}$ = ?,       $P_{2}$ = 5.56 atm  

And, according to ideal gas equation,  

               $\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 $\frac{10.0 atm \times 2.36 L}{298 K} = \frac{5.56 atm \times 7.79 L}{T_{2}}$

            $T_{2}$ = $\frac{43.3124}{0.0792}$ K

                     = 546.87 K

Thus, we can conclude that the final temperature is 546.87 K.