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3 years ago

10

Translate this sentence into an equation.

1 answer:

guajiro [1.7K]3 years ago

8 0

To get this answer, you would want to start by dividing 96 by 6 to find matts score. (Answer 16) then just fill in the equation accordingly! m * 6 = 96

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A store is having a sale in which all items are 20% off. If p is the original price of an item, then the equation p - 0.2p = 0.8

katovenus [111]

Answer:

Answer Expert Verified

We are given that there is a 20% sale in the store. Moreover, the sale price of an item is p - 0.2p, where p is the price of the item. So, we get that, p - 0.2p is equivalent to 0.8p

6 0

2 years ago

The dollar value v(t) of a certain car model that is t years old is given by the following exponential function.

dimaraw [331]

Answer:

v(0) = 32,000 . . . dollars

v(13) = 16,427 . . . dollars

Step-by-step explanation:

The initial value is the value of the function for t=0. Put that into the formula and evaluate.

v(0) = 32,000(0.95^0) = 32,000 . . . . dollars

__

The value after 13 years is the function value for t=13. Put that into the formula and evaluate.

v(13) = 32,000(0.95^13) ≈ 32,000·0.513342 ≈ 16,427 . . . . dollars

5 0

2 years ago

When 8 is subtracted from a certain number and the result is multoplied by 3

Natali [406]

15
15 - 8 = 7
7 • 3 is 21

6 0

3 years ago

Read 2 more answers

A driver travels 208 miles in 4 hours. what is the driver's speen,in miles per hour ?

valina [46]

Answer:

52

Step-by-step explanation:

miles per hour so 208, which is miles and 4 which is hours so 208/4 which is 52

4 0

2 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago