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Alex
2 years ago
8

Emily says that a square is always a rectangle. Jenna says a rectangle is always a square. Who is correct and why are they corre

ct?​
Mathematics
1 answer:
Travka [436]2 years ago
5 0

Answer:

Jenna is right

Step-by-step explanation:

Jenna is right because what makes up a square is its four sides. When calculating the area of a rectangle you use the same formula as you would for a square. A rectangle is just an elongated square.

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Write 72xy^2? as a prime factorization. Show all of your work!​
kolezko [41]

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Answer:

  2³·3²·x·y²

Step-by-step explanation:

Unique prime factors are 2, 3, x, y. Each of those is raised to a power to obtain the given expression.

  72xy² = 8·9·x·y² = 2³·3²·x·y²

6 0
3 years ago
Mary went to the store and spent $4.32 on candy Jessie went to the store and spent $7.32 on snacks. How much more did Jessie spe
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Need help asap!!!<br> (Question:What is 2/3 divided by 4/5?<br><br> (Options: 2/3, 5/6, 1 1/5, 3 1/3
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3 years ago
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To find the standard deviation of the diameter of wooden​ dowels, the manufacturer measures 19 randomly selected dowels and find
loris [4]

Answer:

Option D -  [0.12

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The​ 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of \chi^2 is UC=\chi(\frac{0.05}{2},18) = 31.5264

Lower critical value of \chi^2 is  

LC=\chi(1-\frac{0.05}{2},18) = 8.2307

Lower limit of the 95% confidence interval for the population variance

L=\frac{(df)\times (s^2)}{UC}

L=\frac{18\times (0.16^2)}{31.5264}

L=\frac{18\times0.0256}{31.5264}

L=\frac{0.4608}{31.5264}

L=0.0146

Upper limit of the 95% confidence interval for the population variance

U=\frac{(df)\times(s^2)}{LC}

U=\frac{18\times (0.16^2)}{8.2307}

U=\frac{18\times0.0256}{8.2307}

U=\frac{0.4608}{8.2307}

U=0.0559

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

[\sqrt{0.0146}

[0.1208

or  [0.12

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is  [0.12

6 0
3 years ago
Which times are before 12 in the afternoon on the same day
Oxana [17]

Answer:

1 a.m to 11 a.m

Step-by-step explanation:

It's obvious.

3 0
2 years ago
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