A construction firm bids on two different contracts. Let E1 be the event that the bid on the first contract is successful, and d
efine E2 analogously for the second contract. Suppose that P(E1) = 0.3 and P(E2) = 0.7 and that E1 and E2 are independent events.
1 answer:
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
You might be interested in
Answer:
25/40=13/20
Step-by-step explanation:
just add 9 and 17 which is 26. so it's 26/40. simplify so it's 13/20
Answer:
x = –4
Step-by-step explanation:
x = –koef x / (2•koef x²)
Answer:
<h2>18 + 45m</h2>
Step-by-step explanation:
The distributive property: a(b + c) = ab + ac
9(2 + 5m) = (9)(2) + (9)(5m) = 18 + 45m
Answer:
1. $8.77
2. 498.456
Step-by-step explanation: