A construction firm bids on two different contracts. Let E1 be the event that the bid on the first contract is successful, and d
1 answer:
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Answer:
Step-by-step explanation:
At the first track meet, distance of the shot put throw =
At the second track meet distance of the throw feet
Expression that represents the improvement in the throw will be
D =
D =
D =
D =
D =
D = feet
Mean of the first golfer = 89
Mean of the second golfer = 87
Range of the first golfer = 11
Range of the second golfer = 8
Explanation:
First golfer scores 88, 90, 86, 89, 96 and 85.
Sum of the scores of first golfer = 88 + 90 + 86 + 89 + 96 + 85 = 534
Number of observation of first golfer = 6
Mean of the first golfer =
Mean of the first golfer = 89
Range of the first golfer = Highest score – Lowest score
= 96 – 85
Range of the first golfer = 11
Second golfer scores 91, 86, 88, 84, 90 and 83.
Sum of the scores of second golfer = 91 + 86 + 88 + 84 + 90 + 83 = 522
Number of observation of second golfer = 6
Mean of the second golfer =
Mean of the second golfer = 87
Range of the second golfer = Highest score – Lowest score
= 91 – 83
Range of the second golfer = 8
Comparing the golfer's skills:
Mean of first golfer is greater than Mean of second golfer. (i.e. 89 > 87)
Range of first golfer is greater than Range of second golfer. (i.e. 11 > 8)
Thus, first golfer have more skills than second golfer.
first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!
since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!