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3 years ago

Answer the question below

Mathematics

2 answers:

jenyasd209 [6]3 years ago

7 0

Answer:

y+2=3(x-1)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=3(x-1)

y+2=3(x-1)

Amiraneli [1.4K]3 years ago

3 0

Point slope form y + 2= 3(x - 1)

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Find the measures of the interior angles 110 degrees

Lesechka [4]

Answer:

your answer will be 35

Step-by-step explanation:

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7 0

3 years ago

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Correct the errors and fill in the blanks by completing the square.

zmey [24]

Answer:

x = 2 - 5 $\sqrt{3}$ , x = 2 + 5 $\sqrt{3}$

Step-by-step explanation:

x² - 4x = 71

to complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = 71 + 4

(x - 2)² = 75 ( take the square root of both sides )

x - 2 = ± $\sqrt{75}$ = ± 5 $\sqrt{3}$ ( add 2 to both sides )

x = 2 ± 5 $\sqrt{3}$

then

x = 2 - 5 $\sqrt{3}$ , x = 2 + 5 $\sqrt{3}$

8 0

1 year ago

what is the slope-intercept for of the equation of the line that passes through the point (-6,1) and is perpendicular to the gra

vladimir1956 [14]

The slope that you need to use is 3/2 which is perpendicular to the slope of -2/3.

Use:
y-1=3/2(x+6)
y-1=3x/2 + 9
y=3x/2 + 10

y=3x/2+10 is the final answer

6 0

3 years ago

3. For the polynomial g(x) = x^4 - 8x^3 + 23^2 - 26x + 10, you are told that the zeros include x=1, x = -3 + i, and x = 3+i.

saveliy_v [14]

Step-by-step explanation:

If the polynomial has complex roots, the conjugates of those complex roots must also be part of the zeroes.

Therefore x = -3 - i and x = 3 - i are also zeroes of g(x). However this means that g(x) has 5 solutions when the degree of g(x) is 4. This is impossible, and hence the list is incorrect.

If either of the complex roots (x = -3 + i or x = 3 + i) had a multiplicity of 2, their conjugates will also have a multiplicity of 2, which is impossible as discussed previously.

Therefore x = 1 has a multiplicity of 2.

We have

x⁴ - 8x³ + 23x² - 26x + 10 = (x - 1)²(Ax² + Bx + C).

= (x² - 2x + 1)(Ax² + Bx + C)

= Ax⁴ + (B - 2A)x³ + (A + C - 2B)x² + (B - 2C)x + C

By Comparing Coefficients,

A = 1,

B - 2A = -8,

A + C - 2B = 23,

B - 2C = -26,

C = 10

Solving them we get A = 1, B = -6 and C = 10.

Hence x⁴ - 8x³ + 23x² - 26x + 10

= (x - 1)²(x² - 6x + 10).

Using the Quadratic Formula on x² - 6x + 10,

we find that the correct complex roots are

x = 3 + i and x = 3 - i.

Hence,

the zeroes of g(x) are x = 1, x = 3 + i and x = 3 - i.

8 0

3 years ago

Quadrilateral ABCD has coordinates A(3,5) B(5,2) C(8,4) D(6,7). quadrilateral ABCD is a?

RoseWind [281]

Use the distance formula. The distance formula is:

$\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

If you input the values, you will get:

A to B= $\sqrt{13}$

B to C= $\sqrt{13}$

C to D= $\sqrt{13}$

D to A= $\sqrt{13}$

It is a square.

Hope that helped!

~Cam943, Moderator

7 0

3 years ago

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