Example:
This suggests two solutions,
and
.
However, upon plugging these solutions back into the equation, you get
which checks out, but
does not because
is defined only for
(assuming you're looking for real solutions only). So, we call
an extraneous solution, and the complete solution set (over the real numbers) is
.
Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Area and perimeter are in the ratio of 1:3. but if u mean to ask about the ratio of perimeters & areas of both triangles. the answer would be 1:1
Answer:
9:30 am
Step-by-step explanation:
factors of 10; 5 and 2
factors of 15; 5 and 3
factors of 25; 5 and 5
calculate lcm so, 5x5x3x2 =150
150 mins = 2hr 30mins
7am+2hr30min = 9:30 am
A \greenD{7\,\text{cm} \times 5\,\text{cm}}7cm×5cmstart color #1fab54, 7, start text, c, m, end text, times, 5, start text, c, m
erma4kov [3.2K]
Answer:
The area of the shaded region is 148.04 cm².
Step-by-step explanation:
It is provided that a 7 cm × 5 cm rectangle is inside a circle with radius 6 cm.
The sides of the rectangle are:
l = 7 cm
b = 6 cm.
The radius of the circle is, r = 6 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[\text{l}\times\text{b}]-[\pi\test{r}^{2}]\\\\=[7\times5]+[3.14\times 6\times 6]\\\\=35+113.04\\\\=148.04](https://tex.z-dn.net/?f=%3D%5B%5Ctext%7Bl%7D%5Ctimes%5Ctext%7Bb%7D%5D-%5B%5Cpi%5Ctest%7Br%7D%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B7%5Ctimes5%5D%2B%5B3.14%5Ctimes%206%5Ctimes%206%5D%5C%5C%5C%5C%3D35%2B113.04%5C%5C%5C%5C%3D148.04)
Thus, the area of the shaded region is 148.04 cm².
