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Ainat [17]
3 years ago
15

Veronica sells berries at a farmer's market. She pays $45 for the booth, and earns $5 per pound of berries sold. She sells betwe

en 10 and 30 pounds of berries at each market. The function p(b)=5b−45 represents Veronica's market earnings as a function of pounds of berries sold. What is the practical domain of the function? Please help! Thank you.

Mathematics
2 answers:
Ainat [17]3 years ago
6 0

Veronica typically sells a maximum of 30 pounds of berries but could also sell 10 pounds in the least. Therefore, the PRACTICAL DOMAIN would be between 10 and 30 pounds of berries. This can be expressed in terms of an inequality: 10 ≤ b ≤ 30 (i.e. all integers between 10 and 30 inclusive).

 

If we were to be asked for the THEORETICAL DOMAIN for the same function p(b)=5b−45. We would be considering the set of logical values of b that would generate a reasonable output for the function. Clearly, we could plausibly put any value of b in the function and still get a reasonable output.  So the theoretical domain of the function p(b)=5b−45  is the set of all real numbers.

jasenka [17]3 years ago
4 0

Answer:

Just took the K12 test! the answer was: 10 ≤ b ≤ 30


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How to reduce into simpler terms.?
Sveta_85 [38]

Answer:

The simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

  • A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.
  • In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

\frac{45}{100}

\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}

\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5

\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}

45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20

so

\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}

\mathrm{Cancel\:the\:common\:factor:}\:5

     =\frac{9}{20}

Therefore, the simplest form of the fraction \frac{45}{100}  is  \frac{9}{20}.

i.e.

\frac{45}{100}=\frac{9}{20}

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