There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
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Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
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Whichever method you pick, the answer is: 38
So this problem is asking you to plug numbers in for t. 0 1 2 3 4 5. So your first equation would be 2× 0+8 and you would get 8 so for 0 toppings you would pay 8 dollars then graph this over 0 up 8. Next equation 2×1+8 is 10. Graph. over 1 up 10. Next 2×2+8 is 12. Graph. Over 2 up 12. next 2× 3 + 8 is 14. Graph. Over 3 up 14. Next 2×4+8 is 16 so over 4 up 16. Last 2×5+8 is 18 so over 5 up 18. Your Y-intercept is the dot that is on the y axis and in this problem that is 8. This means if you buy 0 toppings you will spend 8 dollars.
Answer:
Sorry no idea
Step-by-step explanation:
I'm so sorry
Answer:
i don't know sorry
Step-by-step explanation:
