For the first question, all you need to know is that the (amount you want) divided by (the amount of cards total) is the probability of getting the amount you want at random. for example, if there are 3 red marbles in a bag of ten marbles, you divide 3 by 10 (0.30) the probability of picking up a red marble is 30%. try adding up how many cards you want to pick up by the number of cards total.
Answer:
Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution
Step-by-step explanation:
One Tailed Test:
- A one tailed test is a test that have hypothesis of the form

- A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
- Rejection region is the area for which the null hypothesis is rejected.
- If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.
- If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.
Thus, for one tailed test,
Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution
Answer:
<h2>
AB is around 33.18</h2><h2>
BC is around 15.58 </h2>
Step-by-step explanation:
adjacent/hypotenuse is sine:
cos(28 degrees)=29.3/x
cos(28 degrees)*x=29.3
x=29.3/cos(28 degrees)
x=around 33.18
AB is around 33.18
opposite/adjacent is tangent
tan(28 degrees)=x/29.3
tan(28 degrees)*29.3=x
x=tan(28 degrees)*29.3
x=around 15.58
BC is around 15.58
Answer:
Option B.
Step-by-step explanation:
The given vertices of triangle ABC are (-1, -1), (-1, -5) and (0.5, -5).
We need to find the coordinates of triangle when it is translated two units left.
So, the rule of translation is
Using this rule, we get
The vertices of triangle A'B'C' are A'(-3,-1), B'(-3,-5) and C'(-1.5,-5).
Therefore, the correct option is B.
Answer:
or
.
Step-by-step explanation:
How are tangents and secants related to sines and cosines?
.
.
Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem,
. Therefore, for the square of tangents,
.
This equation will thus become:
.
To simplify the calculations, replace all
with another variable. For example, let
. Keep in mind that
.
.
.
Solve this equation for
:
.
.
.
Given that
,
is the only possible solution.
,
, where
(i.e.,
is an integer.)
Given that
,
.
or
. Accordingly,
or
.