Answer:
Prokaryotes.
Explanation:
Most of the Eukaryotes most likely to evolve from the Prokaryotes. Prokaryotes are basically unicellular organisms that lack internal membrane-bound structures. So, they do not carry nucleus and generally have a single chromosome. Most of them have a cell wall outside the plasma membrane, which is a thin layer of lipid that completely surrounds the cell. Prokaryotes reproduce by binary fission method.
Answer:
The division is a taxonomic rank in classifications of the biological organisms used separately in the botany and zoology kingdom. In the botany, the kingdom division is equivalent to the phylum. They include Marchantiophyta, Anthocerotophyta and other phylum-level groups of organisms.
In the zoological kingdom, division refers to a rank use to superordinate to the cohort and subordinate to the infraclass. Living tetrapods are classified to the rank as Divisions Amniota and Amphibia within the group of fleshy limb vertebrates.
<h2>Answer is option "C"</h2>
Explanation:
- NAD+ is a significant co-compound for hydride move catalysts fundamental to numerous metabolic procedures including glycolysis, pyruvate dehydrogenase complex, the TCA cycle and oxidative phosphorylation. The catalysts utilizing NAD+ in hydride-move are known as dehydrogenases or oxidoreductases, which catalyze the decrease of NAD+ into NADH
- NADH shaped from glycolysis (by means of the malate-aspartate transport) or the TCA cycle can respond at Complex I, otherwise called the NADH/coenzyme Q reductase in the mitochondrial electron transport chain [28]. Each NADH devoured by the mitochondria brings about the net creation of 3 ATP atoms (Figure 1). The total oxidation of one glucose atom creates 2 NADH reciprocals in cytosol and 8 NADH particles in mitochondria, empowering creation of 30 ATP counterparts from NADH of the aggregate of 36 ATP counterparts got from the entire procedure of catabolizing glucose to CO2 and H2O.
- Hence, the right answer is option C " the available NAD+ would be converted to NADH and glycolysis would stop due to lack of NAD+.
The answer is c. Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.
Meiosis is a cell division which results in the reduction of chromosome number by half (from diploid to haploid) in daughter cells. It consists of meiosis I and meiosis II.
In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicates which are present as pairs of sister chromatids. When comes to separation, homologous chromosomes separates only, but not sister chromatids. Homologous chromosomes are present only in meiosis I.
In anaphase II, since the cell is haploid, there are 23 chromosomes in duplicates, which are present as sister chromatids. So, in this phase, sister chromatids are those who separates.
Answer:
because to irrigate you need purified or rain water to not kill your plants/animals and once you've used your fresh water how would you get more purified water?
