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MrMuchimi
3 years ago
11

Need help with #1 “how is the equation y= 2x similar to the equation y= 2x + 3?how is it different?”

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

The 2nd one would be different from the first because you are adding 3.

Step-by-step explanation:

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Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
Can some one plz help me with this math qustion
AleksAgata [21]

Answer:

A. =

Step-by-step explanation:

Find a common denominator, then compare.

6 0
3 years ago
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How can you find the area of a semi-circle
quester [9]

In the case of a circle, the formula for area, A, is A = pi * r^2, where r is the circle's radius. Since we know that a semicircle is half of a circle, we can simply divide that equation by two to calculate the area of a semicircle. So, the formula for the area of a semicircle is A = pi * r^2/2

8 0
3 years ago
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3x-15+10m-2x ; x=5 and m=7 <br> evaluate the expression for the given value of the variable.
lianna [129]
3(5)-15+10(7)-2(5)
15-15+70-10
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3 0
3 years ago
WILL GIVE BRAINLIEST PLEASE HELP WITHIN 15 MINUTES!!
Dvinal [7]

Answer:

60 & 42

Step-by-step explanation:

Just know it.

Good Luck!!

3 0
3 years ago
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