We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
<h3><u>Answer:</u></h3>

<h3><u>Step-by-step explanation:</u></h3>
A sequence is given to us is , and we need to find expression for nth term of the sequence. The given sequence is ,

When we flip the numbers , we can clearly see that the number are in Harmonic Progression.
That is when we flip the numbers they are found to be in Arithmetic Progression .
And nth term of an Harmonic Progression is :-

Hence here
- Common difference = 1
- First term = 1 .
<u>Substituting the respective values,</u>

<h3><u>Hence the nth term of the given sequence is given by ¹/n .</u></h3>
Answer:
-3
Step-by-step explanation:
their is your answer