Ask question

Ask question

All categories

3 years ago

11

Dillon decided to construct a rectangular deck in his back yard. It is 16 feet long and 13 feet wide. He is trying to determine

whether he should construct the deck using cedar or a pressure treated material.
The cedar costs $21.09 per square foot for materials.

The pressure treated material costs $18.90 per square foot for materials.
The cost for labor will be the same for either material.

How much money would Dillon save installing a deck with pressure treated material instead of cedar? Explain or show your reasoning. You may use diagrams, drawings, or equations as well as words.

2 answers:

ddd [48]3 years ago

5 0

The labor of the fact that the money is supposed to help Dillon

Mashutka [201]3 years ago

3 0

Answer:

Step-by-step explanation:

d for yearsd for yearsd for yearsd for yearsd for yearsd for yearsd for yearsd for years

You might be interested in

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

Quadrilateral MNQP has vertices as shown. If the figure is translated 4 units left and 3 units down, what are the coordinates of

PilotLPTM [1.2K]

<h3>Answer: (-3, 0)</h3>

Explanation:

Point N is at (1,3)

We apply the rule $(x,y) \to (x-4,y-3)$ which will translate the point 4 units to the left and 3 units down.

The old x coordinate x = 1 becomes x-4 = 1-4 = -3

The old y coordinate y = 3 becomes y-3 = 3-3 = 0

The point N(1,3) moves to N ' (-3, 0)

4 0

2 years ago

What is the answer!???

mr Goodwill [35]

I believe A is the answer!

3 0

3 years ago

Enter the giveaway for points

Nookie1986 [14]

Answer:

Thxx for points how do I enter

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

HELP ASAP Three generous friends, each with some cash, redistribute their money as follows: Ami gives enough money to Jan and To

DENIUS [597]

Answer:

$252

Step-by-step explanation:

This is quite a neat question, with no fixed equation. Given that each person gives the other two enough money to double their cash, if Toy had 36 dollars beginning, and 36 at the end - presumably the cash of each person, ( their starting and original ) should be the same as well. Respectively each should be a multiple of 36 dollars.

Jan's " give away " = Ami + 36, Jan - 108, Toy + 72

Toy's " give away " = Ami + 72, Jan + 36, Toy - 108

Therefore, we can conclude that Ami = 144 at the start, presuming he gave away 108 dollars, with a remaining 36. Jan, having 144 dollars ( after having his 72 dollars doubled by Ami ) gives 36 to Ami to double his amount, and 72 to double Toy's doubled amount, remaining with 36 dollars. Now Ami has 72 dollars, Jan has 36, and Toy has 144. Then, Toy double's Ami and Jan's amount, giving away 72 and 36 dollars, remaining with 36 dollars himself. Therefore, Ami has 144 dollars, Jan has 72 dollars, and Toy has 36 dollars both at the beginning and end.

144 + 72 + 36 = 252 dollars ( in total )

6 0

3 years ago