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Yuki888 [10]
3 years ago
10

The Length is _ and the width is. ?

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0

Answer:

W=10

L=18

Step-by-step explanation:

So the equation for finding the perimeter of a rectangle is


2w + 2l = p


w=width

l=length

p=perimeter


Since the perimeter is 56 feet, and the length is 2 feet less than twice the width, then:

w=?

l=(2w-2)

p=56

So plug this info in-

2w + 2(2w-2) = 56

Then distribute-

2w + 4w - 4 = 56

Combine like terms

6w=60

Divide both sides by six

w=10

And to find length, plug width into the equation for length-

l=(2(10)-2)

l=18

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Describe the sequence of transformations that would take the graph of f(x)=x² to each parabola described below. Focus: (1/4,0),d
ser-zykov [4K]

Answer:

The parabola obtained is x=y²

Step-by-step explanation:

Given the focus (1/4,0) and directrix: x=-1/4

A point on the parabola is determined by the distance of that point with the focus and with the directrix:

Distance between the parabola and the directrix:\sqrt{(x+\frac{1}{4})^{2}  }

Distance between the parabola and the focus:\sqrt{(x-\frac{1}{4})^{2} +(y-0)^{2} }

\sqrt{(x+\frac{1}{4})^{2}}=\sqrt{(x-\frac{1}{4})^{2} +(y-0)^{2} }

(x+\frac{1}{4})^{2}=(x-\frac{1}{4})^{2} +(y-0)^{2}

x^2+\frac{1}{2} x+\frac{1}{16} = x^2-\frac{1}{2} x+\frac{1}{16} + y^{2}

\frac{1}{2} x=-\frac{1}{2} x + y^{2}

\frac{1}{2} x+\frac{1}{2} x = y^{2}

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3 years ago
in a group of 65 players 11 players play basketball only and 33 play cricket only, if the number of players who play cricket is
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Answer: 21 players play basketball
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4 years ago
write and solve the differential equation that models the following statment. "the rate if change of W with respect to x is prop
Vaselesa [24]

Answer:

\int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

Step-by-step explanation:

i)it is given that the rate of change of W with respect to x is proportional to          

     x + 18. Therefore \frac{dW}{dx} = k(x + 18) where k is a constant.

ii) Therefore \int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

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4 0
4 years ago
Please answer quickly.
vladimir2022 [97]

Answer:

1. B. (9, 4)

2. D. (2, -7)

3. C. (20, 30)

4. C. (3/4, -1/5)

Step-by-step explanation:

1.

Eq.1      3x – 5y = 7     Multiply by -2.

Eq. 2    2x + 3y = 30    Multiply by 3.

Eq. 1 becomes: -6x + 10y = -14

Eq. 2 becomes: 6x + 9y = 90

Add the two new equations to get:

19y = 76

y = 4

Now substitute 4 for y in the first original equation and solve for x.

3x - 5(4) = 7

3x -20 = 7

3x = 27

x = 9

Answer: (9, 4)

2.

2x + 3y = -17    Multiply by -2

5x + 2y = -4      Multiply by 3

-4x - 6y = 34

15x + 6y = -12

Add last two equations.

11x = 22

x = 2

Substitute x = 2 into first original equation and solve for y.

2x + 3y = -17

2(2) + 3y = -17

4 + 3y = -17

3y = -21

y = -7

Answer: D. (2, -7)

3.

x + y = 50     Keep equation as it is.

0.05x + 0.06y = 2.8     Multiply by -20.

x + y = 50

-x - 1.2y = -56

Add last two equations.

-0.2y = -6

y = 30

Substitute y = 30 in first original equation and solve for x.

x + y = 50

x + 30 = 50

x = 20

Answer: C. (20, 30)

4.

8g - 5h = 7   Keep as is.

4g + 10h = 1    Multiply by -2.

8g - 5h = 7

-8g - 20h = -2

Add last two equations.

-25h = 5

h = -1/5

Substitute h = -1/5 into h of first original equation and solve for g.

8g - 5h = 7

8g - 5(-1/5) = 7

8g + 1 = 7

8g = 6

g = 6/8

g = 3/4

Answer: C. (3/4, -1/5)

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