The solutions to the system of equations are (-2,-6) and (4,6)
<h3>How to determine the system of equations?</h3>
We have:
-2x + y = -2

Next, we plot the graph of both functions.
From the attached graph, the equations intersect at (-2,-6) and (4,6)
Hence, the solutions to the system of equations are (-2,-6) and (4,6)
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Answer:
The answer is 1-5x+135y
Step-by-step explanation: multiply the numbers 3 and 45 which give you 135
Answer:
k=-1827/685
Step-by-step explanation:
8/9k+9/5=-4-9/7k
8/9k-(-9/7k)=-4-9/5
8/9k+9/7k=-20/5-9/5
56/63k+81/63k=-29/5
137/63k=-29/5
k=(-29/5)/(137/63)
k=(-29/5)(63/137)
k=-1827/685
Step-by-step explanation:
Use the function to find the coordinates of the endpoints. Find the slope between those points, then use point-slope form to write the equation. If you wish, you can simplify to slope-intercept form.
For example, #66:
f(2) = -4(2) + 1 = -7
f(5) = -4(5) + 1 = -19
So the endpoints of the secant line are (2, -7) and (5, -19). The slope between those lines is:
m = (-19 − (-7)) / (5 − 2)
m = -12 / 3
m = -4
The equation of the line in point-slope form is:
y − (-7) = -4 (x − 2)
y + 7 = -4 (x − 2)
Simplifying:
y + 7 = -4x + 8
y = -4x + 1
f(x) is a line, so unsurprisingly, the secant line connecting two points on that line has the same equation.
Let's try #68:
g(2) = (-1)² + 1 = 2
g(5) = (2)² + 1 = 5
So the endpoints of the secant line are (-1, 2) and (2, 5). The slope between those lines is:
m = (5 − 2) / (2 − (-1))
m = 3 / 3
m = 1
The equation of the line in point-slope form is:
y − 2 = 1 (x − (-1))
y − 2 = x + 1
Simplifying:
y = x + 3