Ask question

Ask question

All categories

3 years ago

7

in a group of 65 players 11 players play basketball only and 33 play cricket only, if the number of players who play cricket is

twice the number of players who play Basketball. by using Venn diagram find the number of players who play both games and who do not any game

1 answer:

Eddi Din [679]3 years ago

5 0

Answer: 21 players play basketball

You might be interested in

Which is the graph of the equation Y-2=0.5(x+3)?

Ede4ka [16]

Answer:

..........................

7 0

3 years ago

WILL GIVE BRAINLIEST

jonny [76]

Answer:

A

its the first one

7 0

2 years ago

What is the value of 38.07÷9.4. <br><br>F)0.1453<br>G)1.453<br>H)14.53<br>I) 145.3

Natasha_Volkova [10]

I'm pretty sure the answer is G. I'm not 100% sure tho. Hope this helps! :)

5 0

3 years ago

A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.

Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}$

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}$

6 0

2 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

leonid [27]

Answer:

$\frac{1}{5^{9} }$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$ , then

$5^{-9}$ = $\frac{1}{5^{9} }$

5 0

2 years ago

Read 2 more answers