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3 years ago

7

in a group of 65 players 11 players play basketball only and 33 play cricket only, if the number of players who play cricket is

twice the number of players who play Basketball. by using Venn diagram find the number of players who play both games and who do not any game

1 answer:

Eddi Din [679]3 years ago

5 0

Answer: 21 players play basketball

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The equation `2x - 3 = 4x + 3` is modeled above. What value of `x` makes the equation true?

snow_tiger [21]

X=-3
2x=4x+6
-2x=6
Divide by -2
X=-3

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2 years ago

The graph of y=x^2-4x is shown. name a zero of the function below

hoa [83]

Answer:

0 and 4

Step-by-step explanation:

y = x^2 - 4x can be factored as follows: y = x(x - 4).

We find the zeros by setting this factored form equal to zero and solving for x:

x(x - 4) = 0, or x = 0, or x = 4.

The two zeros of this function are 0 and 4.

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2 years ago

Sally can paint a room in 99 hours while it takes steve 44 hours to paint the same room. how long would it take them to paint th

Lena [83]

I solved a problem like this recently and the answer was the two subtracted, ill say the answer is 55.

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3 years ago

Read 2 more answers

Please answer this correctly

Illusion [34]

Answer:

you did not attach any thing lol

Step-by-step explanation:

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3 years ago

Use the following information to answer this question and the next. Suppose that a recent poll of American households about pet

choli [55]

Answer:

28.75% probability that none of the three randomly selected households own a cat

Step-by-step explanation:

For each household, there are only two possible outcomes. Either it owns a cat, or it does not. The probability of a household owning a cat is independent of other households. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

34% owned a cat

This means that $p = 0.34$

Three households are selected

This means that $n = 3$

What is the probability that none of the three randomly selected households own a cat?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.34)^{0}.(0.66)^{3} = 0.2875$

28.75% probability that none of the three randomly selected households own a cat

5 0

3 years ago